-
huaweiCPP(CHM)
华为C++培训资料C++语言中级教材讲授C++语言的运用技术，包括：类、对象之间的关系、对象的存储与布局、运算符重载、智能指针、仿函数、泛型编程，C++模式设计基本思想。
(C++ language intermediate materials to teach C++ language use of technology, including: classes, relationships between objects, object storage and layout, operator overloading, smart pointer, functor, generic programming, C++ mode design basic idea.)
- 2013-05-05 16:53:08下载
- 积分：1
-
Maze_Engine
数据结构一书上 关于迷宫游戏的算法 (Book on data structure algorithms on maze game)
- 2010-06-12 09:47:17下载
- 积分：1
-
include
1)随机输入平面上n个点的集合；
2)使用分治策略编制计算机程序求出这n个点的极大点。
3)编程实现2维极大点问题的求解，且在程序中体现分治策略。程序能处理任意的n个点。
(1) a collection of n points on a random input plane
2) using divide and conquer strategy computer program to calculate the maximum point of the n point.
3) programming for solving 2 dimensional maximal point problem, and reflect the divide and conquer strategy in the program. Program can handle arbitrary n points.)
- 2015-11-03 15:43:31下载
- 积分：1
-
5.2a版本声子晶体2D案例
利用comsol有限元算法计算声子晶体及其传输特性的一个使用案例！(sonic_crystal_52a_presentation)
- 2020-11-26 08:59:31下载
- 积分：1
-
yanse
说明： 一个基改变对话框的背景颜色于对话框的MFC AppWizard应用程序中(A base to change the background color of dialog in the MFC AppWizard dialog application)
- 2011-02-27 13:00:45下载
- 积分：1
-
03
说明： 《妙趣横生的算法》第三部分原书附带代码程序，绝对属实(" Algorithm for fun," the third part of the original program with the code, the absolute truth)
- 2011-04-24 01:36:18下载
- 积分：1
-
main
以一个m*n的长方阵表示迷宫，0和1分别表示迷宫中的通路和障碍。设计一个程序，对任意设定的迷宫，求出一条从入口到出口的通路，或得出没有通路的结论。
1.基本要求
（1）首先实现一个以链表作存储结构的栈类型，然后编写一个求解迷宫的非递归程序。求得的通路以三元组（i，j，d）的形式输出。其中：（i，j）指示迷宫中的一个坐标，d表示走到下一坐标的方向。如下图所示迷宫。从入口（1，1）到出口（8，8）的求解结果如下：
（1，1）（1，2），（2，2）（3，2）（3，1）（4，1）（5，1）（5，2）（5，3）（6，3）（6，4）（6，5）（5，5）（4，5）（4，6）（4，7）（3，7）（3，8）（4，8）（5，8）（6，8）（7，8）（8，8）(The labyrinth is represented by a m*n rectangular array. 0 and 1 represent the pathways and obstacles in the labyrinth respectively. Design a program for any set of maze, find a way from the entrance to the exit, or draw no conclusion of the path.
1. basic requirements
(1) first implement a stack type with linked list as storage structure, then write a non recursive procedure to solve the maze. The path obtained is output in the form of three tuple (I, J, d). Among them: (I, J) indicates a coordinate in the labyrinth, and D indicates the direction of going to the next coordinate. As shown in the labyrinth below. The results obtained from the entrance (1, 1) to the outlet (8, 8) are as follows:
(1, 1) (1, 2), (2, 2) (3, 2) (3, 1) (4, 1) (4, 1).)
- 2018-07-03 13:15:46下载
- 积分：1
-
VCAD1.0
vc++实践与提高系列 绘图程序v1(vc practice and procedures to enhance family of graphics v1)
- 2005-03-01 15:52:42下载
- 积分：1
-
DESEncryptionDecrypt
编写的DES 对称加解密技术，可随时进行明文密文之间的转换，有需要的朋友可以下载测试！本人目的打算对后台数据库的敏感信息字段用该方法加密，然后用软件权限控制读取，这样即使直接SQL后台取数，也得不到明文数据。(Write DES symmetrical encryption technology, may at any time for conversion between plaintext cipher, friends in need can be download test! I purpose going to the backstage database of sensitive information field with the method of encryption, and then use software to read access control, so even if the SQL backend access directly, also can not get clear data.
)
- 2013-10-15 09:51:35下载
- 积分：1
-
WiFi-8266
说明： stm32+esp8266实现远程控制功能(Using WiFi to realize remote control function)
- 2021-01-12 10:48:49下载
- 积分：1
