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c9
说明： 信道编码的matlab程序，CRC校验码，RS码，卷积码，turbo码，TCM码(Matlab program channel coding, CRC check code, RS code, convolutional codes, turbo codes, TCM code)
- 2010-07-30 15:09:08下载
- 积分：1
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realtime_scheduler_and_control
介绍实时系统的调度算法及控制实例，对实时系统学习者有很好的参考价值(Introduce real-time systems and control instances of scheduling algorithms for real-time systems have a good reference value for learners)
- 2010-01-19 16:06:58下载
- 积分：1
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Matlab-Engineering-App-Experiments
Matlab工程实践课程实验PPT以及部分代码。(Matlab engineering practice course experiment PPT and some code.)
- 2012-06-16 15:58:21下载
- 积分：1
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对msk,fsk,ask等常规调制信号的循环谱进行了仿真 CyclicSpectral
该计算代码主要对msk,fsk,ask等常规调制信号的循环谱进行了仿真，可以进一步补充，谢谢大家分享。(This calculation code mainly cyclic spectrum msk, fsk, ask other conventional modulation signal simulation, can be further supplemented, thank you share.)
- 2020-06-29 13:40:02下载
- 积分：1
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Thermoelastic-Instability-in-a-Seal-Like-Configur
Thermoelastic Instability in a Seal-Like Configuration
- 2013-11-16 12:38:36下载
- 积分：1
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mVmodel
matlab与C的混编，处理乘性噪声，建立M次开根号模型，需要调整参数。(written with matlab and C by S. Yun and H. Woo, "A new multiplicative denoising variational model based on m-th root transformation".)
- 2013-11-12 22:24:03下载
- 积分：1
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声线图的绘制
水声声线仿真，基于射线模型。文章包含仿真条件和说明。文章附件为程序。(Underwater acoustic line simulation, based on the ray model. The article contains simulation conditions and instructions. The article appendix is the procedure.)
- 2018-01-15 15:21:02下载
- 积分：1
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2004113084736415
想保留的成分为cos(2*π*n/3) 带通滤波器，滤除1+cos(2*π*n/3) 的成分，即想保留的成分为cos(π*n/4) 带阻滤波器，滤除cos(π*n/4) 的成分，(Want to keep the ingredients for the cos (2* π* n/3) band-pass filter, filter 1+ Cos (2* π* n/3) of the composition, that is, want to keep the ingredients of cos (π* n/4 ) band-stop filter, filter cos (π* n/4) of the composition,)
- 2009-01-06 13:00:08下载
- 积分：1
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AdjMatrix
source code for SVC(Support Vector Clustering) plot,支持向量聚类画图工具，作者daewonlee(source code for SVC(Support Vector Clustering) plot,by daewonlee)
- 2010-07-08 19:04:53下载
- 积分：1
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anorlderzhi
源码 此程序主要是对二值图像进行操作有效
如对灰度图像进行操作只需要修改部分代码既可以(The main source of this procedure is the binary image to operate effectively on the gray image to operate only need to modify some of the code can)
- 2008-01-06 12:03:11下载
- 积分：1
