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JsonMapper
dahua hikvision test door access control
- 2020-06-24 18:40:02下载
- 积分:1
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飞控源码
说明: 以F407为主控核心实现的多旋翼飞行器飞控系统(Flight Control System of Multi-Rotor Aircraft Based on F407)
- 2019-03-23 19:08:13下载
- 积分:1
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Couduit
在VC上实现与Palm保持同步通信的软件的设计基本步骤合实例!(in VC achieve Palm keep pace with the communications software design example of a basic steps!)
- 2006-07-17 21:22:16下载
- 积分:1
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LPC1788LCD_drive
NXP LPC 1788LCD驅動程序,下載解壓縮即可使使用,不需密碼(NXP LPC 1788LCD driver download unzip to make use of, no password)
- 2013-07-08 15:31:46下载
- 积分:1
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FreeOSEK_rel
OSEK源码文件,可供大家学习交流,多研究研究,对于嵌入式开发有帮助-RealTime Operation System
- 2022-12-25 06:10:04下载
- 积分:1
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Harriscornerdetector
说明: harris 角点检测 MATLAB 代码(Harris corner detection MATLAB code)
- 2010-05-05 10:03:54下载
- 积分:1
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Havel
这是图论里面的一个定理,即Havel定理,它是用来判断一系列的度的序列能否组成一个简单图,在这儿我实现了它。(This is the inside of a theorem of graph theory, that Havel theorem, which is used to determine whether a series of sequences degrees to form a simple graph, here I realized it.)
- 2014-02-25 16:22:50下载
- 积分:1
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Alarm
alarm project IOT based using C
- 2019-02-09 13:28:24下载
- 积分:1
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飞思卡尔智能车竞赛电磁组东北赛区一等奖
第十届飞思卡尔东北赛区电磁组一等奖
- 2022-01-27 21:29:30下载
- 积分:1
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迷宫
迷宫求解:用二维矩阵表示迷宫,自动生成或者直接输入迷宫的格局,确定迷宫是否能走通,如果能走通,输出行走路线。(Labyrinth Solution: Use two-dimensional matrix to represent the maze, automatically generate or directly input the maze pattern, determine whether the maze can pass, if it can pass, output the walking route.)
- 2019-03-21 21:02:04下载
- 积分:1