登录
首页 » Matlab » ULA1一个天线阵的方向图,可以用来估计信号的来波方向,face_direction_pic面阵的方向图 music,MN...

ULA1一个天线阵的方向图,可以用来估计信号的来波方向,face_direction_pic面阵的方向图 music,MN...

于 2022-08-06 发布 文件大小:4.19 kB
0 99
下载积分: 2 下载次数: 2

代码说明:

ULA1一个天线阵的方向图,可以用来估计信号的来波方向,face_direction_pic面阵的方向图 music,MN-music,capon,ESPRINT为四种进测量来波方向的算法 该程序包主要用来测量信号来波的方向,可以应用在通信雷达方面

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Classic_design_iir_filter_matlab
    matlab经典设计iir滤波器Classic design iir filter matlab(Classic design iir filter matlab Classic design iir filter matlab)
    2010-08-02 10:31:38下载
    积分:1
  • deploy_sensor
    this program about how to deploy sensor in certain area.
    2012-06-08 12:32:49下载
    积分:1
  • GSM
    基于梯度相似度的图像质量评价方法,发表在2012年TIP国际期刊上(A. Liu, W. Lin, M. Narwaria, “Image Quality Assessment Based on Gradient Similarity,” IEEE Transactions on Image Processing, vol. 21(4), pp. 1500-1512, 2012.)
    2020-12-04 23:09:23下载
    积分:1
  • picture-of-strip-and-ladder
    可以实现条形图和阶梯图形,导入marlab中很容易实现(picture of strip and ladder)
    2011-12-12 11:09:54下载
    积分:1
  • matlab2660
    matlab实例,给出了诸多matlab编程应用的例子,值得一看。(matlab example, matlab programming gives many examples of applications, worth a visit.)
    2007-11-24 10:35:59下载
    积分:1
  • Hough-Circle-Detection
    基于hough变换的圆形检测,非常好用。(Based on hough transform circle detection, very easy to use.)
    2010-09-16 22:33:52下载
    积分:1
  • quansousuo
    基于malab的全搜索算法是H264块匹配中最基本的算法(Based on the malab the full search algorithm is the H264 algorithm for block matching in the most basic)
    2012-04-22 23:50:06下载
    积分:1
  • Non_linear_Channel_equalizer
    在嘈杂的非线性渠道,采用LMS算法,设计新颖的数字均衡器。(DESIGN OF NOVEL DIGITAL EQUALIZERS FOR NOISY NONLINEAR CHANNEL USING LMS ALGORITHM.)
    2020-09-04 10:28:06下载
    积分:1
  • Rec839_3
    ITU-R国际降雨衰减预测模型之等效雨高的求法 (ITU-R International rain attenuation prediction model of rain rate and method, the simulation model)
    2012-03-08 21:22:59下载
    积分:1
  • File: c9_estimatepi.m have 5 pi estimates are based on a randomized trial to rep...
    %File: c9_estimatepi.m %有5个pi的估计,每一个都是基于500次重复随机试验,所得的pi的五个估计值用以下向量表示 %pi的估计值=[3.0960 3.0720 2.9920 3.1600 3.0480] %如果对5个结果进平均,则pi的估计值=3.0736,这样的结果等价于2500次的试验结果。- File: c9_estimatepi.m have 5 pi estimates are based on a randomized trial to repeat 500 times the income of the five estimated value of pi with the following vector, said the estimated value of pi = [3.0960 3.0720 2.9920 3.1600 3.0480] if the results into an average of 5, then the estimated value of pi = 3.0736, so the result is equivalent to 2500 times the test results.
    2022-01-26 02:51:57下载
    积分:1
  • 696518资源总数
  • 106010会员总数
  • 4今日下载