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ReverseSubstring
Problem Statement
You are given a string input. You are to find the longest substring of input such that the reversal of the substring is also a substring of input. In case of a tie, return the string that occurs earliest in input.
Definition
Class: ReverseSubstring
Method: findReversed
Parameters: string
Returns: string
Method signature: string findReversed(string input)
(be sure your method is public)
Notes
The substring and its reversal may overlap partially or completely.
The entire original string is itself a valid substring (see example 4).
Constraints
input will contain between 1 and 50 characters, inclusive.
Each character of input will be an uppercase letter ( A - Z ).
Examples
0)
"XBCDEFYWFEDCBZ"
Returns: "BCDEF"
We see that the reverse of BCDEF is FEDCB, which appears later in the string.
1)(Problem Statement You are given a string in put. You are to find the longest substring of proficient ut such that the reversal of the substring is als o a substring of input. In case of a tie. return the string that occurs earliest in input . Definition Class : ReverseSubstring Method : findReversed Parameters : string Returns : Method signature string : string findReversed (string input) (be sure yo ur method is public) The Notes and its substring reversal may overlap partially or completely. The entire original string is itself a valid sub string (see example 4). Constraints will input contain between 1 and 50 characters, inclusive. Each character of input will be an up percase letter (A-Z). Examples 0) "XBCDEFYWFE DCBZ "Returns : "BCDEF" We see the reverse of that is)
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简单的贪吃蛇C++源代码
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11087 统计逆序对
Description
设a[0…n-1]是一个包含n个数的数组，若在i<j的情况下，有a[i]>a[j]，则称(i, j)为a数组的一个逆序对（inversion）。
比如 <2,3,8,6,1> 有5个逆序对。请采用类似“合并排序算法”的分治思路以O(nlogn)的效率来实现逆序对的统计。
一个n个元素序列的逆序对个数由三部分构成：
（1）它的左半部分逆序对的个数，（2）加上右半部分逆序对的个数，（3）再加上左半部分元素大于右半部分元素的数量。
其中前两部分（1）和（2）由递归来实现。要保证算法最后效率O(nlogn)，第三部分（3）应该如何实现？
此题请勿采用O(n^2)的简单枚举算法来实现。
并思考如下问题：
（1）怎样的数组含有最多的逆序对？最多的又是多少个呢？
（2）插入排序的运行时间和数组中逆序对的个数有关系吗？什么关系？
输入格式
第一行：n，表示接下来要输入n个元素，n不超过10000。
第二行：n个元素序列。
输出格式
逆序对的个数。
输入样例
5
2 3 8 6 1
输出样例
5(Set a[0... N-1] is a n array containing n numbers. If there is a [i] > a [j] i n the case of I < j, then (i, j) is a n inversion pair of a array.
For example, <2,3,8,6,1> has five reverse pairs. Please use the idea of "merge sorting algorithm" to achieve the statistics of inverse pairs with O (nlogn) efficiency.
The number of inverse pairs of a sequence of n elements consists of three parts:
(1) The number of reverse pairs in the left half, (2) the number of reverse pairs in the right half, (3) the number of elements in the left half is greater than that in the right half.
The first two parts (1) and (2) are implemented by recursion. To ensure the final efficiency of the algorithm O (nlogn), how should the third part (3) be implemented?
Do not use O (n ^ 2) simple enumeration algorithm to solve this problem.)
- 2019-01-07 23:52:06下载
- 积分：1
