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radialdistortion
A simple radial distortion application. Written using OpenGL.
- 2011-05-09 23:27:52下载
- 积分：1
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Single-threaded-file-transfer
实现单线程文件传输，不支持断点传出，功能相对简单，但是性能很好。(Achieve single-threaded file transfer, does not support breakpoints spread, function is relatively simple, but the performance is very good.)
- 2013-06-11 12:51:41下载
- 积分：1
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fem_codes
fem is active queue management technique
- 2013-10-14 01:05:54下载
- 积分：1
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ZT-Series-ZigBee
zigbee的一些基础知识，引脚及其相关协议等(basic zigbee )
- 2011-12-23 17:20:13下载
- 积分：1
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ONVIF2.0协议珍藏版
ONVIF协议， 大华摄像头SDK开发说明(ONVIF protocol, Da Hua camera SDK Development Notes)
- 2018-10-12 01:40:49下载
- 积分：1
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CSCode
说明： 欧 姆 龙 U D P 通 讯(Omron UDP communication)
- 2020-04-21 10:16:21下载
- 积分：1
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C/C++经典面试题
50个C、C 面试题.pdfC/C 经典面试题
- 2020-06-05下载
- 积分：1
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NEWTON
这是一个牛顿插值的例子。输入差值点，计算4次牛顿插值函数值。(This is an example of Newton interpolation. Enter the difference points to calculate the value of 4 Newton interpolation function.)
- 2010-09-08 22:12:37下载
- 积分：1
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medo
设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。 编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits. programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
- 2021-03-22 16:29:16下载
- 积分：1
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1553B-RT
1553B RT功能（使用PCI板卡的通道2实现RT功能，RT的地址和子地址设置需要与BC一致）(1553B RT function (channel 2 using the PCI card to achieve RT function, RT address and subaddress settings need consistent with the BC))
- 2020-11-09 09:29:47下载
- 积分：1
