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Net5-
Net5 是一个支援网路连线的五子棋游戏,可以让你透过网路跟你的亲朋好友
来场五子棋大赛,不过Net5 并没有设计单人的模式,只能利用连线来玩。
(Net5 331 games is a support network connections, allowing you to through the Internet with your friends and family
To field 331 contest, but Net5 and design of single mode, only the use of connection play.)
- 2012-05-17 14:41:19下载
- 积分:1
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PS2mouse
这个是ps2鼠标键盘的程序,基于单片机实现(This is the ps2 mouse and keyboard program, through MCU. Project files can be opened keil)
- 2015-02-05 12:03:24下载
- 积分:1
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opencv 反向投影图
计算直方图并归一化
计算反向投影图
绘制直方图的参数准备
绘制直方图
- 2023-08-18 19:00:03下载
- 积分:1
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学习 .zip
某贸易中心共10层,设有载客电梯1部。为了处理问题的方便,有以下的限定条件: (1) 电梯的运行规则是:可到达每层。 (2) 每部电梯的最大乘员量均为K人(K值可以根据仿真情况在10~20人之间确定)。 (3) 仿真开始时,电梯随机地处于其符合运行规则的任意一层,为空梯。 (4) 仿真开始后,有N人(>20人)在该国际贸易中心的1层,开始乘梯活动。 (5) 每个人初次所要到达的楼层是随机的,开始在底层等待电梯到来。 (6) 每个人乘坐电梯到达指定楼层后,再随机地去往另一楼层,依此类推,当每人乘坐过L次(L值可以根据仿真情况在3~10次之间确定)电梯后,第L+1次为下至底层并结束乘梯行为。到所有人结束乘梯行为时,本次仿真结束。 (7) 电梯运行速度为S秒/层(S值可以根据仿真情况在1~5之间确定),每人上下时间为T秒(T值可以根据仿真情况在2~10之间确定)。 (8) 电梯运行的方向由先发出请求者决定,不允许后发出请求者改变电梯的当前运行方向,除非是未被请求的空梯。(a total of 10 layers, with a passenger elevator. To address the issue of convenience, have the following qualifications : (a) lift the operating rules is : can be reached on each floor. (2) each lift crew of the largest volume of all K (K value can be based on the simulation of the 10 to 20 between determined). (3) simulation at the beginning, randomly located in the lift line with its rules of operation arbitrary layer of air staircase. (4) simulation began, a N (gt; 20) at the International Trade Center in one layer, started by ladder activities. (5) Each person must first reach the floors are random, in the bottom wait for the elevator arrived. (6) Each person taken the lift arrived at the designated floor and then another random foot to the floor, and so on, when each rode L (L value c)
- 2021-04-22 14:48:48下载
- 积分:1
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lisanduishu
设p是素数,a是p的本原根,即a1,a2,a3,…,ap-1在mod p下产生1到p-1的所有值,所以对任何b属于{1,…,p-1},有唯一的i属于{1,…,p-1}使得ai mod p 等于p。称i为模p下以a为底b的离散对数。(P is a prime number based, a is the primitive root p, that is, a1, a2, a3, ..., ap-1 in the mod p under 1 to p-1 for all values, so for any b belongs to (1, ..., p-1), there are only i belong to (1, ..., p-1) makes ai mod p equivalent to p. Said i was under the modulus p to a for b at the end of the discrete logarithm.)
- 2009-06-16 17:44:18下载
- 积分:1
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B3g_phase2
B3g_phase2_C语言_Matlab程序及说明(_Matlab Procedures and B3g_phase2_C language description)
- 2007-09-07 10:22:52下载
- 积分:1
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点名系统
简单的点名系统啊森林砍伐哈看克拉可以实现点名机制
- 2022-01-25 14:39:48下载
- 积分:1
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duobiaotidai
一个周期3的多表代替密码,第1个表由密钥字法产生(密钥字自拟),第2个表由洗牌法产生(注意,字母a~z与数字0~25一一对应),第三个表由公式法产生(数学公式自拟,注意它须是Z26上的一个一一变换)(a cycle of three multi-table instead of passwords, a table by key word method, (key word from the intended), Table No. 2 produced by shuffling method (note, a letter with a number of z ~ 0 ~ 25 he gathers), 3rd tables generated by the formula (from the proposed mathematical formula, it should pay attention to the Z26 is a transformation on January 1))
- 2006-10-10 17:33:56下载
- 积分:1
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adhoc-network
对学习AD HOC网络很有帮助的一些电子文档,可以了解此网络的基本原理和一些协议之间的比较,以及改进。大家看看肯定会有所帮助哦(The study of electronic document helpful AD HOC network)
- 2012-03-10 20:31:57下载
- 积分:1
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Mobile-VOIP_Based_on_SIP
移动IP的协议栈源码,与大家共享,希望有人能用得上(Mobile IP protocol stack source code, and share the hope that someone can use the grain)
- 2007-01-17 11:25:22下载
- 积分:1