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program
包括emd分解程序,求边际谱程序,hilbert包络解调程序,求取小波包频带能量程序,K均值聚类程序(fault diagnosis program)
- 2014-08-05 12:22:22下载
- 积分:1
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AODV
truetime 的例子(I),介绍AODV,使用truetime2.0(truetime example (I))
- 2010-08-21 21:10:59下载
- 积分:1
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bbnnekf
neural network trained with unscented kalman filter
- 2009-04-23 01:37:47下载
- 积分:1
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matlabcodingtoachieve
霍夫曼编码、算术编码和行程编码的matlab实现(Huffman coding, arithmetic coding and routing matlab coding to achieve)
- 2009-05-25 17:40:22下载
- 积分:1
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FCMandCFCM
说明: FCM算法是应用最广泛的聚类分析方法之一,CFCM也是模糊数学中的一种聚类分析算法。
现在给出的这两个算法是C++代码实现的。 (FCM algorithm is the most widely used method of cluster analysis, CFCM is a kind of fuzzy clustering analysis in the algorithm. Now given by the two algorithms is the C++ code to achieve.)
- 2009-07-27 17:03:28下载
- 积分:1
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real_data_influence
MATLAB仿真OFDM过采样的东西,主要的星座图和每一个子载波上对应的星座图也被观察到。(MATLAB simulation OFDM sample things, the main constellation chart and each is the carrier of the corresponding constellation chart has been observed.)
- 2011-09-14 17:07:48下载
- 积分:1
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power_1phPWM_IGBT
Single-Phase PWM Inverter
This demonstration illustrates use of the IGBT/Diode block in voltage-sourced converters. It also demonstrates harmonic analysis of PWM waveforms using the Powergui/FFT tool.
- 2014-10-25 23:34:54下载
- 积分:1
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music(doa)
七单元天线阵MUSIC DOA估计:
d=1 , 天线阵元的间距;
lma=2, 信号中心波长;
四输入信号;
A=[A1,A2,A3,A4], 得出A矩;
四信号的频率d=[1.3*cos(v1*n)
1*sin(v2*n)
1*sin(v3*n)
1*sin(v4*n)]
构造输入信号矢量
U=A*d
总的输入信号
总输入信号的协方差矩阵
[s,h]=eig(c)
求协方差的特征矢量及特征值
取出与零特征值对应的特征矢量
求协方差矩阵的逆矩阵
应用Music法估计输出
绘出各波达方向图(Seven-element antenna array MUSIC DOA estimates: d = 1, Antenna Array pitch LMA = 2 signal center wavelength four input signals A = [A1, A2, A3, and A4], drawn A moment tetra-frequency of the signal D = [1.3* cos (V1* n) 1* sin (v2* n) 1* sin (v3* n) 1* sin (V4* n)] constructed input signal vector U = A* D of the total input signal of the total input signal covariance matrix [S] = EIG (c) seeking covariance feature vector and the feature value removing and corresponding to the zero eigenvalues characterized vector seeking covariance matrix inverse matrix Applications Music estimate output plotted DOA Figure)
- 2013-04-15 23:48:49下载
- 积分:1
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hibernate_annotation
hinbernate的练习适合新手的学习和使用。(Three practical feasibility of SSH framework)
- 2015-03-04 19:18:07下载
- 积分:1
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3zuoye
某市有一码头,每次仅容一辆船停泊装卸货,由于经常有船等候进港,部分人提出要扩建码头。经过调查历史资料发现,码头平均每月停船24艘,每艘船的停泊时间为24±20小时,相邻两艘船的到达时间间隔为30±15小时,如果一艘船因有船在港而等候1小时,其消耗成本为1000元。经预算,扩建码头大约需要1350万元,故市长决策如下:如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头,否则,不予扩建。因此,希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间,对于此问题用概率统计的方法来做比较复杂,可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊,多次模拟预测停泊情况,以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)
- 2015-04-17 18:59:46下载
- 积分:1