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M文件1
通过编程得到正交的1egendre(N)函数序列(Orthogonal sequence of Legendre (N) functions obtained by programming)
- 2020-06-24 16:00:01下载
- 积分：1
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jm
jake s model ,信道仿真的一种，在matlab上仿真实现。(jake s model ,matlab code )
- 2014-01-03 16:27:34下载
- 积分：1
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CurvatureEstimationsam
a function to calculate Curvature in 2D curve
- 2013-08-18 03:26:12下载
- 积分：1
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RBF-network-sliding
基于RBF网络补偿的控制输入受限滑模控制(Compensation control based on RBF network sliding mode control input constraints)
- 2013-11-11 13:42:58下载
- 积分：1
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B
说明： Forest fire detection code
- 2016-03-12 15:31:03下载
- 积分：1
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matfg1
The proposed approach satisfies the
integrability condition and does not need any boundary
condition assumptio-ns, we have designed a stand-alone,
flexible Matlab implementation that enables to
evaluation the proposed approach. The experiments on
real images show the approaches ability to reconstruction
the surface from SFS.
- 2010-11-21 01:47:14下载
- 积分：1
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MATLAB_Primer_7th_Ed
The purpose of this Primer is to
help you begin to use MATLAB. It is not intended to be
a substitute for the online help facility or the MATLAB
documentation (such as Getting Started with MATLAB,
available in printed form and online). The Primer can
best be used hands-on. You are encouraged to work at
the computer as you read the Primer and freely
experiment with the examples. This Primer, along with
the online help facility, usually suffices for students in a
class requiring the use of MATLAB.
- 2008-07-13 22:34:17下载
- 积分：1
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Helmholtz
用迭代法在MATLAB中实现（赫姆霍兹）Helmholtz方程组的求解(Solving Helmholtz equation set by iterative method in MATLAB)
- 2013-07-18 23:04:33下载
- 积分：1
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KALMAN
卡尔曼滤波在低轨卫星精密定轨中的应用,对于初学者来说是比较好的学习资料~~~~(Kalman filter in LEO satellite precise orbit determination in the application, is a good learning materials for beginners ~ ~ ~ ~)
- 2021-03-18 20:09:19下载
- 积分：1
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Economic-Dispatch
本代码采用二次规划求解电力系统经济调度问题，具有快速的计算速度。(The attached code used to solve the economic dispatch problem for power system operation is easy-implemented and high-efficiency. Only for study. Thank you!)
- 2020-07-30 16:08:38下载
- 积分：1
