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2
说明： 有一个长度为整数L(1<=L<=10000)的马路，可以想象成数轴上长度为L的一个线段，起点是坐标原点，在每个整数坐标点有一棵树，即在0,1,2，...，L共L+1个位置上有L+1棵树。
现在要移走一些树，移走的树的区间用一对数字表示，如 100 200表示移走从100到200之间（包括端点）所有的树。
可能有M(1<=M<=100)个区间，区间之间可能有重叠。现在要求移走所有区间的树之后剩下的树的个数。
输入：
两个整数L(1<=L<=10000)和M(1<=M<=100)。
接下来有M组整数，每组有一对数字。
输出：
可能有多组输入数据，对于每组输入数据，输出一个数，表示移走所有区间的树之后剩下的树的个数。(Has a length of integer L (1 < = L < = 10000) of the road, one can imagine a number line segment of length L, the starting point is the coordinate origin, each integer coordinate points in a tree, i.e. 0,1 , 2, ..., L total has L+1 L+1 positions on the tree. Now to remove some trees, tree removed by a range of digitally represented, such as 100 200 represents removed (inclusive) between 100 and 200 all the trees. There may be M (1 < = M < = 100) intervals, there may be overlap between the intervals. Now, after the number of trees require the removal of all remaining sections of the tree. Input: two integer L (1 < = L < = 10000) and M (1 < = M < = 100). Then there is an integer M groups, each with a pair of numbers. Output: there may be multiple sets of input data, for each set of input data, the output of a number indicating the number of the removal of all remaining sections of the tree after tree.)
- 2015-03-22 23:35:47下载
- 积分：1
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Vis
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- 2014-01-08 22:59:33下载
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OFDM_MATLAB
MATLAB上实现的OFDM+AWGN/Rayleigh+BPSK/QPSK/16QAM/64QAM，并分析EbN0 vs BER.(The MATLAB implementation OFDM+AWGN/Rayleigh+BPSK/QPSK/16QAM/64QAM, and analyze EbN0 vs BER.)
- 2014-09-22 06:27:48下载
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- 2013-12-24 03:38:03下载
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(The MATLAB program PID control for robot path, the path selection is a sine function simply control parameters and angular velocities. Has been tested.)
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