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Numbersequence
说明： 简单的数据结构算法 在POJ上的题目 利用C++实现(Simple data structure algorithm in POJ on the subject using C++ Implementation)
- 2010-05-04 19:03:45下载
- 积分：1
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ds3
单向链表的创建与操作
设单向链表中节点的数据域的数据类型为整型，编写函数实现以下操作：
（1）实现单向链表的创建（包括初始化）与输出操作，节点的个数及节点的数据由用户输入。
（源代码：ds3-1.c）
（2）查找给定的单链表中的第i个节点，并将其地址返回。若不存在第i个节点，则返回空地址。
（源代码：ds3-2.c）
（3）查找给定的单链表中值为n的节点，并将其地址返回。若不存在值为n的节点，则返回空地址。同时，还应通过参数传回该节点的序号。
（源代码：ds3-3.c）
（4）删除给定的单链表中的第i个节点，成功返回1，失败返回0。
（源代码：ds3-4.c）
（5）删除给定的单链表中值为n的节点，成功返回1，失败返回0。
（源代码：ds3-5.c）
（6）在给定的单链表的第i位上插入值为n的节点。
（源代码：ds3-6.c）
（7）在给定单链表的值为m的节点的前面插入一个值为n的节点。
（源代码：ds3-7.c）
(Creation and operation of a one-way linked list
Set up a one-way linked list data type node integer data fields , write a function to achieve the following:
( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user .
( Source : ds3-1.c)
( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address.
( Source : ds3-2.c)
( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node .
( Source : ds3-3.c)
( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 .
( Source : ds3-4.c)
( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 .
( Source : ds3-5.c)
( 6 ) )
- 2014-05-11 19:19:41下载
- 积分：1
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Map-four-staining
用不多于四种颜色为地图染色，使相邻的行政区不重色，是计算机科学中著名的“四染色”的典型应用，应用这个思想，是以回溯的算法对一幅给定的地图染色。是对数据结构中栈的应用。(With no more than four colors map staining the adjacent borough is not heavy color, typical applications of computer science "stain" the application of this idea, a backtracking algorithm on a given mapstaining. The application of the stack data structure.)
- 2012-12-05 13:20:37下载
- 积分：1
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1_1
最小生成树算法 克鲁斯法尔算法 球最佳路径(kulru method class maiun void cx )
- 2009-09-13 22:45:01下载
- 积分：1
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yinhangmoni
这是一个简单的银行模拟系统
1、 客户的到达时间随机
2、 客户需要处理的业务随机（不同业务处理的平均长度不同，例如：取款时间较短，开户和销户时间较长）
3、 处理客户业务所需时间随机（在一定范围内）
4、 使用文本文件记录每个客户到达时间、业务处理时间、业务结束时间
5、 动态显示（刷新时间可调）目前每个窗口累计处理客户数量、等待人数，每个窗口的平均业务处理时间，不同业务类型业务的累计办理量。
(This is a simple bank simulation system
1 customer arrival time random
2, customers need to deal with the business of random (the average length of the different business processes, such as: the withdrawal shorter, longer to open an account and cancel the account)
3, the time required to deal with customer service random (within certain limits)
4, using a text file to record each customer arrival time, business processing time, the business end of time
5 dynamically display (refresh time is adjustable) each window is accumulated to handle the number of customers waiting for the number the average business processing time of each window, different type of business operations total for the amount.)
- 2012-11-22 00:08:18下载
- 积分：1
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migong
输入迷宫行列数，1代表墙0代表路，之后系统生成路径(Enter the maze ranks number 1 represents 0 for Wall Road, after the system-generated path)
- 2016-05-14 20:16:00下载
- 积分：1
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jhgrerfgjz
一个简单的求矩阵求逆的c语言算法
一个简单的求矩阵求逆的c语言算法
一个简单的求矩阵求逆的c语言算法(a simple matrix inversion for the C language algorithms for a simple matrix inversion of the c language a simple algorithm The matrix inversion for the C language algorithms for a simple matrix inversion algorithm in C Language)
- 2021-03-29 11:39:11下载
- 积分：1
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BinarySearchTree
在Visual Studio 2008运行成功 数据结构 二叉查找树的类(In Visual Studio 2008 running a successful binary search tree data structure classes)
- 2013-07-23 22:04:29下载
- 积分：1
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maze
迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)
- 2013-12-13 17:55:45下载
- 积分：1
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44
说明： 给定程序中，函数fun的功能是：将a所指3×5矩阵中第k列的元素左移到第0列，第k列以后的每列元素依次左移，原来左边的各列依次绕道右边。
例如，有以下矩阵：
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
若k结果为2，程序执行结果为：
3 4 5 1 2
3 4 5 1 2
3 4 5 1 2
请在程序的下划线处填入正确的内容并把下划线删除，使程序得出正确的结果。
注意：源文件存放在考生文件夹下的BLANK1.C中
不得增行或删行，也不得更改程序的结构！
(A given program, function fun feature is: a 3 × 5 matrix referred to in the first k elements of the left column to move Section 0, the k elements of each column after column followed by the left, the original columns in the left turn Bypass on the right. For example, the following matrix: 123,451,234,512,345 If k is 2, the program execution results: 345,123,451,234,512 in the program underscore the right content at the fill and to remove the underscore, so that the program reach the right result. Note: The source files in the folder of BLANK1.C candidates are not allowed by the line or delete line, nor change the structure of the program!)
- 2011-08-11 07:53:10下载
- 积分：1
