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junitperf-1.9.1
Junitperf实际是基于junit的包装，通过编写用于junitperf的单元测试，我们也可使测试过程自动化。(Junitperf actually junit-based packaging, through the preparation for the junitperf unit testing, we also can automate the testing process.)
- 2010-01-04 15:57:29下载
- 积分：1
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MurrachsBeginningJava2
Murrach s Beginning Java 2.rar
ebook..
- 2010-09-06 16:33:13下载
- 积分：1
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Demo
一个J2SE的简单入门，很快就能读懂的，希望对新手的些帮助(Introduction to a simple J2SE soon will be able to read and I hope that more help for the novice)
- 2009-04-15 11:19:09下载
- 积分：1
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DxUtil
check Verify Exception Source Code for Andriod.
- 2013-12-02 14:15:02下载
- 积分：1
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TestWebSerivce
XFire+WebService+Spring简单Demo(XFire+WebService+Spring Demo)
- 2013-06-05 11:11:13下载
- 积分：1
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phonegap-2.9.0
phonegap-2.9.0.zip,最新phonegap(phonegap-2.9.0.zip, latest phonegap)
- 2013-10-15 10:36:28下载
- 积分：1
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Windows
这是一个最简单的通信软件 里面包含了一些基本的通信知识(dfsffsd)
- 2009-02-19 19:56:30下载
- 积分：1
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飞机大战网络版
网络版JAVA版飞机大战，自己在学习JAVA网络开发时写的小栗子(Network version JAVA version of the aircraft war,Xiao Chestnut Written by myself in Learning JAVA Network Development)
- 2020-07-04 03:20:02下载
- 积分：1
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Optimizing-the-Normalized-Dead-Time_2
optimal scheduling techicoptimal scheduling techic
- 2011-10-23 09:53:45下载
- 积分：1
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Java进阶篇课设
说明： 实现扑克牌，一副牌中抽去大小王剩下52张（如果初练也可只用1～10这40张牌)，任意抽取4张牌（称牌组)，用加、减、乘、除（可加括号)把牌面上的数算成24。每张牌必须用一次且只能用一次，如抽出的牌是3、8、8、9，那么算式为（9-8)×8×3或3×8+（9-8)或（9- 8÷8)×3等。(In order to realize playing cards, 52 cards are removed from a deck (only 40 cards can be used for the first practice). Four cards are randomly selected (called card groups). The number on the deck is calculated as 24 by adding, subtracting, multiplying and dividing (brackets can be added). Each card must be used once and only once. If the drawn card is 3, 8, 8, 9, the formula is (9-8)*8*3 or 3*8+ (9-8) or (9-8 8)*3)
- 2020-12-31 16:18:59下载
- 积分：1
