baotong

代码说明：

  一个报童从报刊发行中心订报后零售，每卖一份报纸可赚钱a元；若报纸卖不出去，则退回发行处，每退一份要赔钱b元。每天报童卖出的份数是随机的，但报童可以根据以往卖报情况统计得到每天卖k份报纸的概率密度p(k)。 （1） 求报童每天期望收益达到最大（或损失达到最小）的定报量z。 （2） 改变参数a/b的值，观察订报量的最优值变化，画出变化曲线。 试画出仿真流程图，进行程序实现，并对仿真结果进行分析。 (A newsboy subscribe from the press after the retail distribution centers, each sale of a newspaper can make money a million if newspapers can not be sold, then returned to Issue Department, each retire to a loss of a b element. Newsboy sold shares in a day is random, but the newsboy can sell based on past statistics reported to be selling daily newspaper k the probability density p (k). (1) seeking newsboy expected profit per day to maximize (or minimize loss) reported that the volume of fixed-z. (2) change the parameters a/b values, subscribe to observe changes in the volume of the optimal value, draw curve. Simulation test to draw a flow chart for program realization, and simulation results for analysis.)