newton

代码说明：

  用牛顿迭代法求方程 f(x)=x³ -x² -1=0 在x。=1.5附近的一个实根。取§=0.000001，取最大迭代数为60. (With Newton iteration equation for f (x) = x ³-x ² -1 = 0 in x. = 1.5 near the root of a real. Take § = 0.000001, take the largest number of 60 iterations.)