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wavelet
2代小波示意程序，此程序用提升法实现第二代小波变换
(two generation wavelet indicate procedures, the procedures used to enhance law to achieve the second generation wavelet transform)
- 2007-07-08 10:33:40下载
- 积分：1
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music
this file generate a MUSIC function
- 2010-10-19 16:06:51下载
- 积分：1
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polar-matlab
自己编写的polar码 编译码算法程序 matlab 可用(polarcode matlab)
- 2021-03-05 10:49:31下载
- 积分：1
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速度调节器
开关磁阻电动机仿真用的功能控制模块啊啊啊啊啊(shzaibuzhidaoshuodianshaa)
- 2019-04-24 12:58:01下载
- 积分：1
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quanjiaqi
建立了基于matlab语言的四位全加器仿真模型，通过了系统验证。(Matlab language is established based on four full adder simulation model, verified by the system.)
- 2010-09-27 15:50:28下载
- 积分：1
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mathlab
说明： 这些源程序是最优化里的一些优化方法，用于解决简单函数，和多维函数的问题！(wegstein hair, is to optimize the course of a demand extreme value method for a simple function, find solutions and high precision!)
- 2010-03-22 12:05:40下载
- 积分：1
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ofdm
matlab 下OFDM信号的产生、发送和接收以及误码率分析等(matlab generated under the OFDM signal, send and receive, and BER analysis)
- 2011-06-03 20:43:20下载
- 积分：1
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pingmianbo
采用平面波展开法求解二维光子晶体能带，有正方形和六边形(Plane wave expansion method for solving two-dimensional photonic crystal band)
- 2014-09-04 09:47:09下载
- 积分：1
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cd
<最优化及matlab的应用>课后题的编程(Most optimized operating)
- 2013-10-20 07:46:40下载
- 积分：1
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1
说明： 一种未知信源数的高分辨DOA 估计算法：众多性能优良的超分辨波达方向(DOA)估计算法通常需要预先判定信源数目，然而，现有的信源数估计
算法在有限采样快拍条件下，估计性能随着信噪比的降低而下降，错误概率也相应增加，最终导致DOA 估计失败。
该文提出一种超分辨的DOA 估计算法，此算法不需要预判信源个数和进行特征值分解，同时在时变环境中，针对
快拍数较少的情况下，依然保持较高的角度分辨能力，可以被认为是综合了Capon 法和MUSIC 法的优点。(Algorithm on High Resolution DOA Estimation
without Sources Number：Many of the super resolution DOA(Direction-Of-Arrival) estimation algorithms presume the number of
signal sources. Since the sample snapshot is limited, however, the available algorithms on source number estimation
may fail at lower SNR. In this paper, a novel algorithm for high resolution DOA estimation is proposed, which not
only skips sources number estimation and EVD, but also behaves satisfactorily with a few snapshot, it may be
viewed as a combination of merit of conventional Capon and MUSIC method.)
- 2013-12-30 18:29:20下载
- 积分：1
