登录
首页 » C++ Builder » OFDM_CODE

OFDM_CODE

于 2011-01-04 发布 文件大小:862KB
0 183
下载积分: 1 下载次数: 14

代码说明:

  详细介绍了ofdm的发送模块、接收模块及信道估计(Ofdm described in detail the transmission module, receiver module and Channel Estimation)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • RadarDataShow
    这是有关综合实例——雷达工程数据的可视化与处理(This is the comprehensive example, the radar engineering data visualization and processing)
    2012-04-27 14:43:43下载
    积分:1
  • HOTQ1
    一个非常红的画图程序,非常有意思,再此上传下(A very red paint program, very interesting, upload it again next)
    2011-10-04 09:52:14下载
    积分:1
  • COA_LABS
    its a file concatanation program
    2010-01-25 12:49:11下载
    积分:1
  • HMMDemo
    HMM人脸识别在MATLAB平台下的源代码,能够实现准确的人脸识别(HMM recognition in MATLAB platform s source code, provides a range of programs)
    2015-01-08 11:41:42下载
    积分:1
  • setmodem
    说明:  一个用于CDPD调制解调器参数设置的程序。(a CDPD modem for parameter setting procedure.)
    2006-04-03 12:29:05下载
    积分:1
  • CGfxOutBarCtrl
    CGfxOutBarCtrl类源码和使用实例,类库中包括了如下文件的下载:   GfxOutBarCtrl.h、GfxOutBarCtrl.cpp、GfxGroupEdit.cpp、GfxGroupEdit.h、GfxPopupMenu.cpp、GfxPopupMenu.h。(CGfxOutBarCtrl class source code and use cases, class libraries are included in the following documents to download: GfxOutBarCtrl.h, GfxOutBarCtrl.cpp, GfxGroupEdit.cpp, GfxGroupEdit.h, GfxPopupMenu.cpp, GfxPopupMenu.h.)
    2015-02-24 14:10:37下载
    积分:1
  • Bbeiijingyidoa
    背景移动补偿技术的研究,是关于车辆检测期间对于背景移动的情况进进行的补偿技术的改进性的研究,希望对大家有所帮助。 已通过测试。 (Background compensation mobile technology, are about the context of vehicle detection during the moovement for the compensation technique to improve the research, hoping for U.S. help. Have passed the )
    2012-05-18 15:55:16下载
    积分:1
  • EvaluateReversePolishNotation
    Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, *, /. Each operand may be an integer or another expression. Some examples: [ 2 , 1 , + , 3 , * ] -> ((2 + 1) * 3) -> 9 [ 4 , 13 , 5 , / , + ] -> (4 + (13 / 5)) -> 6 分析:这一题就是写程序计算逆波兰式的结果,遍历表达式,碰到操作数入栈,碰到操作符就从栈顶取出两个操作数,再将计算后的结果入栈,最后栈中剩余的唯一操作数就是计算结果。(. Evaluate the value of an arithmetic expression in Reverse Polish Notation Valid operators are+,-,*,/Each operand may be an integer or another expression Some examples:.. [" 2" , " 1" , " +" , " 3 " ," * " ]-> ((2+ 1)* 3)-> 9 [" 4 " ," 13 " ," 5 " ," /" ," + " ]-> (4+ (13/After this problem is to write a program to calculate the inverse Polish results, iterate expression operand stack encounter, encounter operator to fetch two operands the stack, and then calculated as follows:> 6 Analysis- 5)) The results of the stack, the only remaining operand stack is the final calculations.)
    2015-03-15 23:06:09下载
    积分:1
  • Matlab
    《MATLAB7.0从入门到精通》全书源码,包括使用说明。(MATLAB7.0 From Novice to Professional book source code, including instructions for use.)
    2010-09-16 16:43:34下载
    积分:1
  • matlabgjxhs
    matlab所有的工具箱函数大全,包括了所有的工具箱函数。 (all the Matlab toolbox functions Solutions, including all of the toolbox functions. Matlab toolbox functions of all volumes, including all the Toolbox function.)
    2007-06-25 14:40:10下载
    积分:1
  • 696518资源总数
  • 106148会员总数
  • 10今日下载