用“时域最小平方误差准则” 设计IIR DF

代码说明：

  试用时域最小平方误差准则（最小平方逆设计）设计一个具有四项系数的IIR DF的系统函数，使其在y(n)=[3,2,1]输入激励下，输出v(n)逼近d(n)=[2,0.2,0.05]。令v(-1)=v(-2)=0。求出v(n)的前8个样值与d(n)进行比较。用matlab实现了此要求。(trial at the least square error domain guidelines (minimum inverse square design) design with a four DF IIR coefficient of the system function, so in y (n) = [3,2,1] incentive to import, export v (n) approximation d (n) = [2,0.2,0.05]. So v (1) = v (2) = 0. Get v (n) of eight samples value d (n) comparisons. Using Matlab realization of this request.)