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111
function pi = solve2(count,m,cc)
借助布冯投针实验 仿真求pi的值
pi=0
frq=0
randNo = binornd(1,cc,1,m)
pro=zeros(1,count)
for j=1:count
for i = 1:m
if randNo(1,i) == 1
frq = frq + 1
end
pro(i) = frq/i
end
pi = (2*m)/frq
pro(j) = pi
end
pro = pro,num =1:count
plot(num,pro) (function pi = solve2 (count, m, cc) to vote with Buffon needle experiment simulation find the value of pi pi = 0 frq = 0 randNo = binornd (1, cc, 1, m) pro = zeros (1, count) for j = 1: count for i = 1: m if randNo (1, i) == 1 frq = frq+ 1 end pro (i) = frq/i end pi = (2* m )/frq pro (j) = pi end pro = pro, num = 1: count plot (num, pro) )
- 2011-05-24 15:39:41下载
- 积分：1
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这是一个非常重要的而又简单的程序，是书上常用和数学建模的好帮手(nice work
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- 积分：1
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时延和丢包的网络控制系统的补偿控制分析研究 Control-of-Network-System
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- 2011-12-16 11:41:29下载
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利用正弦信号作为发射信号，分别在AWGN和瑞利信道中，计算CR中的检测概率和虚警概率，并绘图。(Sinusoidal signal as transmitted signal, respectively, in AWGN and Rayleigh channel, calculate the probability of detection and false alarm probability of CR and drawing.)
- 2014-02-18 11:20:23下载
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用MATLAB编写的rbfnn程序，共同学习(Rbfnn programs written with MATLAB, learning together)
- 2010-12-14 11:14:58下载
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- 2014-07-05 21:46:50下载
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code matlab pr low filter
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- 2015-05-23 17:09:19下载
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偏微分方程组求解,一维动态偏微分方程MATLAB实例(solving PDEs)
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