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SA
说明: 模拟退火GUI演示,利用模拟退火算法求全局最大值最小值(Simulated annealing GUI demonstration, the use of simulated annealing algorithm seeking the global maximum value of the minimum)
- 2009-11-09 00:42:19下载
- 积分:1
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channel_jxy
说明: 无线通信工程仿真中用到的信道模型,适用于MIMO-OFDM仿真。(wireless communications engineering simulation used in the channel model, applied to MIMO-OFDM simulation.)
- 2006-05-14 14:43:28下载
- 积分:1
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narcissusC
水仙花数的C实现,很不错的,我感觉。希望能对大伙有用,谢谢大家(narcissus)
- 2010-05-13 12:14:29下载
- 积分:1
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Matlab-FIR
FIR低通滤波器设计,运行通过,通过改变滤波器参数,可以得到不同阶数的滤波器,加有随机噪声的语音信号通过滤波器后会有很大改善。(FIR low-pass filter design, to run through, can be obtained by varying the filter parameters, the number of filters of different orders, and added with the random noise of the speech signal through the filter will be greatly improved.)
- 2013-01-17 12:05:53下载
- 积分:1
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vad_code
this is acode of voice activity detction
- 2013-05-11 22:41:21下载
- 积分:1
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MATLAB-30-ANN
入门好书《MATLAB神经网络30个案例分析》,连同源程序,许多应用范例(good book for matlab ANN)
- 2014-02-19 14:11:35下载
- 积分:1
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image-denoising-techniquesy
a research based study on various image noise filters and denoise techniques
- 2014-09-11 13:48:01下载
- 积分:1
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code
confun fundamental code
- 2012-09-13 05:47:50下载
- 积分:1
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edge
在matlab,传统的边缘检测直接调用edge函数,但是得到的边缘信息较稀薄,可以通过将sobel,roberts,prewitt三种算子的边缘检测叠加起来,并且对于连续的边缘部分拓宽,使得边缘更连贯清晰(In matlab, traditional edge detection edge direct call function, but thinner than the edge information can be obtained by sobel, roberts, prewitt three edge detection operator stack up, and for widening the continuous edge portion, so that the edge is more consistent clear)
- 2013-12-21 15:16:36下载
- 积分:1
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fano
设有离散无记忆信源X,P(X).二进制费诺编码为:1.将信源符号按概率从大到小的顺序排列2.将信源分成两组――按两组概率之差为最小分.3.上面一组编码为0,下面一组编码为1,一直分到一组只有一个信源为止.4.将一个信源分组得到的0和1全部连接起来,组成该信源的码字,信源即得到自己的费诺编码.(There be no X remembering the message source in case that having being scattered, binary Feinuo of P (X) code is: 1. Will believe that the source sign orders 2 according to probability is minor from arriving at greatly sequence. Will believe that the source divides into two part being allotted 3 according to two set of bad of probability for the minimum. A group of code is 0 above , a group of code is 1 underneath, till dividing till a group only when one believes a source 4. Get up with a 0 and 1 all connection believing that the source is divided into groups and , be composed of the codon owing message a source , believe that the source is to get self Feinuo code
Powered )
- 2009-11-27 12:04:44下载
- 积分:1