-
improvednewton2
给定一个三次方程,改进的Newton法求解,并研究各种算法的收敛阶数.(Given a cubic equation, improved Newton method and to study the convergence of various algorithms order.)
- 2008-03-01 17:48:37下载
- 积分：1
-
matlab_code
用matlab实现卷积，并且分析步长不同对结果的影响。(Convolution using matlab implementation, and analysis of the different steps of the results.)
- 2011-09-04 14:06:46下载
- 积分：1
-
ICA的具体算法流程及对TE过程进行故障检测的应用
ICA的具体算法流程及对TE过程进行故障检测的应用(ICA and fault detection on TE)
- 2020-10-17 21:37:27下载
- 积分：1
-
MATLAB
the program content qum psk modulation and demodulation techniques in matlab.
- 2013-08-21 13:51:12下载
- 积分：1
-
Nonlinear-time-series
一本关于非线性时间序列分析的书籍，本来论坛有人上传过，但不能下载了。(One on nonlinear time series analysis of books，Originally it was uploaded, but can not download)
- 2013-10-06 15:46:27下载
- 积分：1
-
matlab
基于MATLAB的声音滤波及加噪文件的处理实验结果源代码(song wave document or with noise filter with matlab and other tread)
- 2012-05-01 15:36:13下载
- 积分：1
-
Jump_main
本程序为跳扩散过程下欧式期权的定价模型，方便大家做出期权走势图(The procedures for the jump diffusion process European option pricing model, we facilitate to make a chart options)
- 2013-09-23 09:34:45下载
- 积分：1
-
MATLAB-Power-System-Analysis
介绍了如何通过matlab仿真软件进行电力系统仿真分析(Describes how matlab simulation software for power system simulation and analysis)
- 2013-11-08 19:32:03下载
- 积分：1
-
Fzcx2
10kv配电网单相接地故障仿真模型，可实现直配线路及带分支线路的仿真，还可以直接观察到故障后电压电流信息的模分量(10kV single phase to earth fault of distribution network simulation model)
- 2015-03-31 16:44:39下载
- 积分：1
-
szfxsy1
实验一：三次样条插值（P56，例6）
一、实验目的：
1) 掌握三次样条插值的运用
2) 了解拉格朗日插值在高次上的误差
二、实验环境：Matlab6.5
三、实验内容：
1) 给定函数f(x)=1/(1+x2)，-5<=x<=5，节点xk=-5+k，(k=0,1,2…10)，用三次样条插值求S10(x)，S10’(-5)=f’(-5)，S10’(5)=f’(5)。
2）作原函数f(x)，拉格朗日插值函数Ln(x)，三次样条差值函数Sn(x)。画出三个函数的图像，比较它们的区别。
(Experiment I: cubic spline interpolation (P56, cases of 6) First, the experiment was: 1) cubic spline interpolation to master the use of 2) understanding of Lagrange interpolation in high-error second, experimental environment: Matlab6 .5 c, experimental elements: 1) a given function f (x) = 1/(1+ x2),-5 <= x <= 5, node xk =- 5+ k, (k = 0,1,2 ... 10), using cubic spline interpolation for S10 (x), S10 (-5) = f (-5), S10 (5) = f (5). 2) for the original function f (x), the Lagrange interpolation function Ln (x), cubic spline difference function Sn (x). Draw the three functions of images, compare the difference between them.)
- 2009-01-18 23:06:15下载
- 积分：1
