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watermatlabppt

于 2008-09-02 发布文件大小:1081KB

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说明：用matlab做的博士毕业论文讲解,里面包括算法值得参考(Using matlab to do a PhD thesis on, which include the algorithm it is also useful)

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lvchenglinnlms
这里主要对LMS算法及一些改进的LMS算法（NLMS算法、变步长LMS算法、变换域LMS算法）之间的不同点进行了比较，在传统的LMS算法的基础上发展了LMS算法的应用。另一方面又从RLS算法的分析中对其与LMS算法的不同特性进行了比较，很值得研究！(The key players here and some of the LMS algorithm is an improved LMS algorithm (NLMS algorithm, variable step size LMS algorithm, transform domain LMS algorithm) the differences between the points of comparison, in the traditional LMS algorithm is developed on the basis of the LMS algorithm applications. On the other hand and from the analysis of RLS algorithm and LMS algorithm for its different characteristics were compared, it is worth studying!)

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《MATLAB电机仿真精华50例》源代码习题源码直流电动机 mdl(answer key)

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说明：给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值第三行n个正整数n,表示物品重量输出:第一行表示总价值第二行n个数(0/1),0表示物品不装入,1表示装入例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)

2009-07-01 23:07:01下载

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suspension system of a half car

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nodeinsertbeforenodeancestor
param factory document factory, may not be null Source Code for Andriod.

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说明： Kalman filter word document

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Creates pushbutton uicontrol labeled with TeX or LaTeX strings

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watermatlabppt

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