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ASN1PBERPDER
asn1编码说明，详细说明了asn1编码格式，以及der编码，ber编码(asn1 encoding instructions detailing asn1 encoding formats and coding der)
- 2015-02-06 14:57:39下载
- 积分：1
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CreatingGraphicalUserInterfaces
一本介绍matlab GUI编程的书，里面包括了各种控件的编程，比如菜单、编辑框、按钮、列表框等。(An introduction matlab GUI programming books, which include a variety of control programming, such as menus, edit boxes, buttons, list boxes and so on.)
- 2010-06-13 23:55:44下载
- 积分：1
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MATLAB-c
msk的调制解调MATLAB源代码，很不错，值得看看(msk modulation and demodulation MATLAB source code, very good, worth a look)
- 2013-11-15 16:35:31下载
- 积分：1
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Signal-generator
自己按照下载的信号发生器源程序编写调试，调试成功(Signal generator in accordance with their own source code download write debugging, debugging success)
- 2011-10-23 16:55:29下载
- 积分：1
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LDPC
LDPC的译码算法，其中使用matlab和C的联合编程，C主要做了译码算法，并且有性能的仿真测试(LDPC decoding algorithm, including joint programming matlab and C, C major to do the decoding algorithm and performance simulation test)
- 2021-05-07 08:58:37下载
- 积分：1
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qjyz
全局阈值程序，用于matlab中图像分割，能够对比强烈的图片进行较好的分割。(Global threshold program, used in matlab image segmentation, can be used to better segmentation contrast images.
)
- 2013-11-06 09:14:50下载
- 积分：1
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art-cpp
《實戰C++ — 八個別具特色的實作經驗》與目前市面㆖ 眾多C++ 書籍的最大不同，在於
本書既非基礎觀念之教㈻ 書籍，亦非開發工具之使用手冊，而是以「㆒ 章㆒ 專案」的方式，
從實際應用面引領讀者領略C++。
本書是《The Art of C++》的㆗ 文譯本。原作者Herbert Schildt 是㆒ 位㈻ ㈲ 專精、著作等身的
IT 技術作家，其作品普遍獲得良好評價。(err)
- 2007-11-22 15:39:38下载
- 积分：1
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VirtualKD20
用虚拟机COM方式很慢.试试用这个吧,这个据说能提高十几倍哟.里面的read.txt文件我在VMWare中安装做了一下简要的中文说明.
irpfind produces ~450KB/s traffic on VirtualBox and ~150KB/s on VMWare, significantly outperforming standard ~10KB/s COM Port(COM way using virtual machine is slow. Try it with this, this is said to increase more than tenfold yo. Read.txt document inside VMWare installed, I have done a brief description of the Chinese. Irpfind produces ~ 450KB/s traffic on VirtualBox and ~ 150KB/s on VMWare, significantly outperforming standard ~ 10KB/s COM Port)
- 2009-07-07 11:37:07下载
- 积分：1
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PCB
这是code使用说明,对大家比较有帮助，新手必备(This is the code for use)
- 2013-12-01 18:22:12下载
- 积分：1
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0
说明： 给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入.
输入:第一行两个正整数n(物品数)和C(容量)
第二行n个正整数n,表示物品价值
第三行n个正整数n,表示物品重量
输出:第一行表示总价值
第二行n个数(0/1),0表示物品不装入,1表示装入
例如,
输入:
5 10
6 3 5 4 6
2 2 6 5 4
输出
15
1 1 0 0 1
(Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)
- 2009-07-01 23:07:01下载
- 积分：1
