登录
首页 » matlab » zhouchenggund

zhouchenggund

于 2008-09-25 发布 文件大小:1KB
0 226
下载积分: 1 下载次数: 2

代码说明:

说明:  轴承滚动体故障诊断代码,内含频率计算,大家一起学习(Rolling Element Bearing Fault Diagnosis code, containing the frequency calculation, everyone learning together)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • ldpc11111
    LDPC码的编解码Matlab仿真 希望对大家有用(LDPC codes codec Matlab simulation hope useful for everyone)
    2008-06-08 19:29:31下载
    积分:1
  • xiaobofenxiMATLABshixian
    小波分析的应用及其MATLAB程序实现,caj格式(Application of wavelet analysis and MATLAB program, caj format)
    2008-12-29 15:06:28下载
    积分:1
  • MATLAB
    里面含有丰富的MATLAB资料供大家使用,堪称MATLAB资料大全(Which contain rich information for people to use MATLAB, called MATLAB Sourcebook)
    2010-05-19 12:45:07下载
    积分:1
  • PassiveSignal
    对地毫米波辐射计波形仿真,里面有仿真思路,及源码(To millimeter-wave radiometer waveform simulation, there are simulation ideas, and the source)
    2012-08-11 20:57:57下载
    积分:1
  • dct
    code is based on the satellite filter based technique dct compressioin
    2013-05-13 15:07:53下载
    积分:1
  • GPCXX
    这是一个多彩文字显示的系统模块源码GPCXX,分享给同学们学习参考(This is a colorful text display system module source code DCWZXSMK, share to the students to learn reference)
    2017-02-21 19:48:26下载
    积分:1
  • dir2cas
    直接型到级联型的形式转换 % [b0,B,A]=dir2cas(b,a) %b 为直接型的分子多项式系数 %a 为直接型的分母多项式系数 %b0为增益系数 %B 为包含各bk的K乘3维实系数矩阵 %A 为包含各ak的K乘3维实系数矩阵 %(directly to the cascade-type conversion in the form of%% [belts, B, A] = dir2cas (b, a)% b-to direct the molecular polynomial coefficients% for a direct-denominator polynomial coefficients% of the gain coefficient belts% B To contain the bk K by the three-dimensional real coefficient matrix% A to include all ak K by the three-dimensional real coefficient matrix%)
    2006-11-06 09:03:56下载
    积分:1
  • xxt
    用C编写的地震资料楔形体模型,可以变换参数,简单通用(Written using C seismic data wedge model, may come and go parameters, simple and universal)
    2010-07-14 09:38:00下载
    积分:1
  • rect2grid
    Grid generation for irregular perimeter. Uses rect.m and fps.m.
    2009-10-15 17:47:10下载
    积分:1
  • base
    1.分别在两个图中画出δ(n)和δ(n-2),其中-10≤n≤10,画出U(n)其中-10≤n≤10。 2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n),0≤n≤10和x2(n)=(0.8)n,1≤n≤6。 3.由上一题,计算y(n)=x1(n)+x2(n),并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)
    2010-11-26 16:34:06下载
    积分:1
  • 696518资源总数
  • 105873会员总数
  • 12今日下载