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01bagProblemGreedy
0／1背包问题的贪心优化解法 邓宏涛朱蜘
(江汉大学数学与计算机学院武汉430056)
摘要：介绍了0／1背包问题的基本贪心算法的解决策略，通过对贪心算法的改进和优化，找出0／1背包问题的最优解
的很好近似。(0/1 knapsack problem greedy optimization method of邓宏涛Zhu spider (Jianghan University, Mathematics and Computer Science, Wuhan 430056) Abstract: 0/1 knapsack problem of the greedy algorithm to solve the basic strategy of the greedy algorithm through the improvement and optimization, to find 0/1 knapsack problem of the optimal solution of a very good approximation.)
- 2009-05-28 17:28:47下载
- 积分：1
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guicompensation_fig
current consumption calculation in gui
- 2010-11-18 23:34:04下载
- 积分：1
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cyclo
dynamic voltage restorer for sag and swell
- 2013-11-20 22:41:39下载
- 积分：1
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ofdm-2channelest
OFDM ls和LMMSE的信道估计。比较详细，可以运行结果。(The OFDM ls and LMMSE the channel estimation. In more detail, you can run the results.)
- 2013-04-30 03:27:20下载
- 积分：1
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MISO_MU
这个程序是用来仿真多小区多用户，已知信道信息，采用OFDM，QPSK调制下的误码性能分析，特点是将预编码参数放在频域处理。(This program is used to simulate multi-user multi-cell, known channel information, using OFDM, QPSK modulation BER performance under analysis, is characterized by the pre-coding parameters on the frequency domain.)
- 2021-05-07 21:04:36下载
- 积分：1
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WCDMA_DownlinkSimulator
这是一个基于WCDMA系统的 MIMO－OFDM下行链路的仿真模型。(This is a WCDMA system based on MIMO-OFDM downlink simulation model.)
- 2007-05-10 10:13:50下载
- 积分：1
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Untitledddd14daac
ieee14节点含有直流输电的atc程序，可以计算14节点优化后有直流量的系统atc(atc procedures as ieee14 node DC, 14 nodes can be calculated to optimize straight flow system atc)
- 2012-06-05 10:27:02下载
- 积分：1
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CurvatureEstimationsam
a function to calculate Curvature in 2D curve
- 2013-08-18 03:26:12下载
- 积分：1
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SGM
说明： 立体匹配SGM算法matlab实现，包括图像预处理，census特征计算、4条扫描线代价聚合、亚像素求精等后处理步骤(Matlab implementation of stereo matching SGM algorithm, including image preprocessing, census feature calculation, four scanning line cost aggregation, sub-pixel refinement and other post-processing steps)
- 2021-04-02 14:09:07下载
- 积分：1
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总线输出使用功率流解决方案
该程序将打印在屏幕上的表格形式的功率流的解决方案。运行使用Lineflow.m和启发式方法的功率流解决方案全面迭代后，Busout.m方法论上设有输出
- 2022-07-11 09:21:30下载
- 积分：1
