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matlab-and-simulink
《matlab/simulink 通信系统建模与仿真》一书所有源代码以及模块,希望对初学者有所帮助("Matlab/simulink communications system modeling and simulation," a book all the source code and modules, I hope to help beginners)
- 2014-05-26 10:02:16下载
- 积分:1
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and-gate
programming of and gate
- 2016-11-22 14:30:48下载
- 积分:1
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fuzzyPID2
说明: 另外一个模糊pid控制器matlab程序,没有用到simulink,但也很实用,希望对大家有所帮助!(good)
- 2009-08-13 19:11:28下载
- 积分:1
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Holographic-spectrum
全息谱的matlab代码以及应用。包含一个全息谱文件和一个应用文件。(Holographic spectrum matlab code. Contains a holospectrum file and an application file.)
- 2013-05-14 11:05:05下载
- 积分:1
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pcm
该段程序完成了由输入信号抽样值到pcm的编码过程.(The section of program completed by the input signal value to the pcm coding process.)
- 2010-10-30 15:51:37下载
- 积分:1
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F10
NEURO-FUZZY LOGIC SYSTEMS
MATLAB TOOLBOX GUI
- 2013-03-11 21:21:38下载
- 积分:1
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lianxufenliyouhua
利用matlab编写的根据连续分离变量方法设计的优化程序包(Using matlab to prepare the basis for a continuous optimization of separation of variables designed package)
- 2009-11-04 16:05:54下载
- 积分:1
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base
1.分别在两个图中画出δ(n)和δ(n-2),其中-10≤n≤10,画出U(n)其中-10≤n≤10。
2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n),0≤n≤10和x2(n)=(0.8)n,1≤n≤6。
3.由上一题,计算y(n)=x1(n)+x2(n),并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)
- 2010-11-26 16:34:06下载
- 积分:1
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Tarea-Clasificacion
Ejemplo de clasificacion de caracterisiticas utilizando inteligencia de particulas y red multicuadratica
- 2013-08-01 01:59:19下载
- 积分:1
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filter
实现低通,高通,带通的不同类型滤波器,并用几个基本的函数进行了验证(Low pass, high pass, the different types of band-pass filter, and a few basic functions were verified)
- 2013-04-17 14:19:54下载
- 积分:1