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formula4
Optimization of 2 dimensional Labyrinth (Maze) representation for tiny memory
- 2009-06-25 16:27:47下载
- 积分：1
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qaiqingbeng
是小学期课程设计的题目，包含特征值与特征向量的提取、训练样本以及最后的识别，多机电力系统仿真及其潮流计算。( Is the topic of the elementary school stage curriculum design, Contains the eigenvalue and eigenvector extraction, the training sample, and the final recognition, Multi-machine power system simulation and flow calculation.)
- 2017-04-19 12:09:32下载
- 积分：1
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EGT_v1p3
书籍The Epipolar Geometry Toolbox (EGT)的MATLAB源代码(Books The Epipolar Geometry Toolbox (EGT) of the MATLAB source code)
- 2008-05-20 16:39:17下载
- 积分：1
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Log
有了合适的处理对象，剩下的就是技术问题了。在数字运动检测中运用的关键技术有图像数据读取、图像的中值滤波、图像灰度化、图像梯度的获取、图像特征区域的确定、两幅图像的匹配、图像二值化、图像细化、图像去离散点的操作、物体的区域定位、物体中心点的取得，最后再从图片中得到物体运动轨迹。本运动检测系统是为了实现对一系列图片中运动物体的跟踪而设计的，它通过对一系列图片的处理，提取出图片背景，识别出运动物体，进而对运动物体进行跟踪，得到物体运动的轨迹。本文主要阐述了什么是数字图像处理、数字图像处理的基本要求、数字图像处理的实践及开发工具的特点、功能、()
- 2008-05-24 13:11:44下载
- 积分：1
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svd
本程序可以实现对图像用Matlab进行奇异值分解(This program enables the images to use Matlab the singular value decomposition)
- 2010-01-07 15:37:54下载
- 积分：1
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IR
说明： 对IQ接收器最重要的两个参数,即I和Q两路分量之间的幅度一致性和相位正交性,可采
用如下办法计算:把I、Q 两路信号分别作FFT ,找出频域内信号的幅度,即可算得两路分量的幅度一
致性 把I、Q两路信号合成一个复数信号,作FFT ,对得到的频谱求镜像抑制比(即频域内的信号与信号镜像的幅度比) ,通过镜像抑制比和幅度一致性,可求出接收机的I和Q两路分量之间的相位正交性。(IQ receiver for the two most important parameters, namely I and Q components of two-way consistency between the amplitude and phase orthogonality may be adopted calculated using the following method: to I, Q 2 signals, respectively for FFT, to find a frequency domain signal amplitude, can be considered as two-way component caused by the range of 1 the I, Q 2 signals into one complex signal for FFT, the spectrum demand of the received image rejection ratio (ie, frequency domain signal and magnitude of the signal mirror ratio), through the image rejection ratio and extent of consistency, the receiver can be derived I and Q phase between the two-way component orthogonality.)
- 2009-09-21 17:57:34下载
- 积分：1
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data-structure-part2
说明： 源码包括清华大学出版社数据结构书第4~6章对应的源码。个人认为比书上的一些代码还要精简。所有代码均通过调试运行(Source data structure including the Tsinghua University Press Book No. 4 ~ 6 s corresponds to the source. Personally think that the ratio of the number of books but also to streamline the code. Debug all the code to run through)
- 2009-08-12 14:58:45下载
- 积分：1
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VC++深入详解code
说明： Visual C++基础开发指南，是一款面向初学者学习者的指导教材，内附代码！(Visual C++ basic development guide, is a guide for beginners learning materials, with code!)
- 2020-06-22 19:00:02下载
- 积分：1
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[计算机程序的构造和解释].(中文版）.清晰版.pdf
关于lisp和计算机的程序的理解,相当有价值的一本书 适合初学者。有一定经验者可适当观看(about scheme the dialect of lisp)
- 2018-09-24 10:07:38下载
- 积分：1
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C语言编程实验
各种C语言基础练习及代码答案，适合C语言初学者。(Basic C language exercises and code answers.)
- 2020-06-23 22:20:02下载
- 积分：1
