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RegistryKey
说明: 获取硬盘物理序列号,用来对软件加密,vs2008工程。(HD number)
- 2010-04-14 13:53:13下载
- 积分:1
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DESsystem
说明: DES加密算法,C++编写,有界面有录像,写的很详细的大项目(DES encryption algorithm, C++ written, there is a video interface, written in large projects in great detail)
- 2011-04-10 21:12:01下载
- 积分:1
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Shift Cipher
说明: 一个移位加密算法的源代码,跟大家交流一下。(a shift encryption algorithm source code sharing with you what.)
- 2005-12-01 09:21:24下载
- 积分:1
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EC-Signature
基于miracl大数库的椭圆曲线EC的签名算法的c语言实现(Database based on large numbers miracl elliptic curve signature algorithm EC for c-language implementation)
- 2020-07-03 18:40:02下载
- 积分:1
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SFZ
身份证15位转18位的算法原码,可以自动将转换后的结果放入剪贴板中(Algorithm of the original code ID card 15 turn 18, you can automatically converted into the clipboard)
- 2012-08-22 12:17:21下载
- 积分:1
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RSA加解密算法
信息安全中的RSA算法,界面简单明了,功能齐全(information security of the RSA algorithm, simple interface, the full range of functions)
- 2005-07-01 17:50:39下载
- 积分:1
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ECCCBuilder
说明: ECC实现加密解密功能,系统参数的生成!(ECC to achieve encryption and decryption functions, system parameter generation!)
- 2010-03-28 18:27:24下载
- 积分:1
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sanpack_rsa_vs2003sln
看到RSA加密的C++类下载的人不少,我也下载了,并且稍微改动了一下,使它看上去更加易懂。在新年随手写了一套RSA文件加密,用win32dll封装使用了这个类,用C#写了文件加密和操作界面,可以实现密钥的保存和对任何文件的RSA加密操作。送给大家祝大家新年快乐。(see RSA encryption C downloaded to many people, I have downloaded and slightly altered a bit it looks more comprehensible. New Year threw in a written document RSA encryption, win32dll Compliant with the use of this category, C# to write document encryption and interface, can achieve key to the preservation of any documents and the RSA encryption operation. Give you wish you a happy New Year.)
- 2006-09-25 23:18:10下载
- 积分:1
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ssrc
软件加密 使用MD5算法对密码进行加密
软件加密 使用MD5算法对密码进行加密(Software encryption using MD5 algorithm to encrypt passwords)
- 2014-09-15 16:58:53下载
- 积分:1
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ASFDSAF
题目:某个公司采用公用电话传递数据,数据是四位的整数,在传递过程中是加密的,加密规则如下:
每位数字都加上5,然后用和除以10的余数代替该数字,再将第一位和第四位交换,第二位和第三位交换。
1.程序分析:
2.程序源代码:(Topic: a company USES the public telephone relay data, data is four integers, in the relay in the process is encrypted, encryption rules are as follows:
Each Numbers add 5, then use and divided by the number of 10 instead of a remnant, then the first and fourth exchange, the second and third exchange.
1. The program analysis:
2. The source code:)
- 2012-05-26 20:07:28下载
- 积分:1