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equ_response2

于 2010-06-23 发布文件大小:1KB

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equalizer response for channel F(Z)=-.2Z^2+.5Z^1+1+.5Z^-1-.2Z^-2 for zfl and tap=7,9,15

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equ_response2.m,1160,2010-06-08

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equ_response2

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