-
FFT_IFFT
自己编的程序,实现快速傅里叶变化,结果和matlab自带的fft2一样。(Own series of programs, fast Fourier transform, results and matlab native fft2 the same.)
- 2010-07-05 22:47:09下载
- 积分:1
-
small_signal_linear_nonlinear12.mdl
small signal analysis for Induction motor
- 2012-02-05 22:39:32下载
- 积分:1
-
三点定位MATLAB代码
三点定位算法,利用MATLAB进行仿真,亲测有效。。。(Three-point positioning algorithm, using MATLAB for simulation, pro-test effective)
- 2019-01-09 15:08:57下载
- 积分:1
-
msk
通信系统中,连续相位调制(msk)与解调的MATLAB实现。(Communication systems, continuous-phase modulation (msk) and demodulation of MATLAB to achieve.)
- 2008-12-14 16:18:22下载
- 积分:1
-
abcd
Adaptive Schemes for Expanded Diagnosis Image Evaluation for skin cancer
Skin cancer is a malignant tumour which grows in skin cells. It is one of the most common of all cancer which affects human beings and accounts for more than 50 of all types of cancers around the world.
Skin cancer is skin’s unwanted growth with differing causes and varying degrees of malignancies. It can spread very fast to all organs/parts of human body through lymphatic system or blood.
- 2015-02-24 00:31:14下载
- 积分:1
-
jm
说明: jake s model ,信道仿真的一种,在matlab上仿真实现。(jake s model ,matlab code )
- 2014-01-03 16:27:34下载
- 积分:1
-
GEPSVM
这是原始的最接近特征值支持向量机的源代码,希望对大家有帮助。(its origin code of gepsvm,i hope it is hopeful。)
- 2021-01-13 19:58:49下载
- 积分:1
-
cyclostationspectrum-estimation-
循环平稳信号的空间谱估计课件,应该对大家有帮助(Spatial spectrum estimation cyclostationary signals)
- 2014-03-24 22:08:55下载
- 积分:1
-
filter
读入语音信号,加入噪声后将其滤除再还原声音(Adding a pulse noise to an existed speech then filt it with a specified FIR filter.)
- 2010-07-18 23:24:53下载
- 积分:1
-
pi_method1
Estimated number of Pi ( Method 1)
how do we estimate Pi by simulation? In the simulation, you keep throwing darts at random onto the dartboard. All of the darts fall within the square, but not all of them fall within the circle. Here s the key. If you throw darts completely at random, this experiment estimate the ratio of the area of the circle to the area of the square, by counting the number of darts in each.
Our study of the geometry tells us this ratio is Pi/4. So, now we can estimate Pi as
- 2013-04-29 02:49:47下载
- 积分:1