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strcon
对于给定的n个字符串，请找出一种最佳的连接方式，使得采用该连接方式得到的字符串在所有连接的结果中，字典序最小(For a given n-string, find an optimal connection, making use of the connection string to get the results in all connections, the lexicographic minimum)
- 2011-09-02 16:52:40下载
- 积分：1
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paixu
实现冒泡，快速，希尔排序法。并计算，比较他的次数。(Achieve bubbling fast shell sort. And calculate, compare the number of times.)
- 2012-05-21 22:13:12下载
- 积分：1
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MyKD Tree
KD树算法，能够实现对点云数据进行压缩，非常简单，适用于初学者(KD tree algorithm, can achieve the point cloud data compression, very simple, suitable for beginners)
- 2015-06-24 20:10:33下载
- 积分：1
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mofanwenti
魔方问题
数据结构
使用c++
经典问题(Cube problem
Data Structure
Using c++
Classic problem)
- 2014-01-08 22:30:48下载
- 积分：1
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arc
运用二叉树求代数表达式的值，将代数表达式的每个符号用二叉树结点表示，遍历图的每一结点，按结点值得不同采用不同运算方式(Solving algebraic expressions binary tree)
- 2012-06-23 19:52:38下载
- 积分：1
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classical-algorithm-VCPP
常用的算法经典代码，包括快速排序，冒泡排序等各种排序方法，还有二叉树的前序、中序和后序遍历等(The classic algorithm code, including quick sort and bubble sort sorting methods, as well as the preamble of the binary tree, inorder and postorder traversal, etc.)
- 2013-01-15 11:15:10下载
- 积分：1
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Brute-force-algorithm
穷举算法，VC中的经典程序之一，适合初学者，(Brute-force algorithm, the the of the classic procedures in in the the VC, suitable for beginners)
- 2012-06-06 21:20:06下载
- 积分：1
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zuiyouerfenjiansuozhu
最优二叉搜索树问题具有最优子结构性质，即其任意一棵子树都是一棵独立的最优二叉搜索树，所以可以采用动态规划方法，并且在每次更新时保存子树的根。(Optimal binary search tree problem has optimal substructure property that any of its sub-tree are an independent optimal binary search tree, so you can use dynamic programming methods, and save each update subtree roots.)
- 2013-10-10 18:48:17下载
- 积分：1
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hafumanTree
数据结构课程设计，在VC环境下完成，利用哈夫曼树原理，主要功能是实现字符的压缩和解压缩，设计脉络清晰，易懂(Data structure course design, completed in the VC environment, using Huffman tree principle, the main function is to achieve the character of the compression and decompression, design, clear structure, easy to understand)
- 2011-01-02 13:15:23下载
- 积分：1
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Huffman
霍夫曼编码实验报告，内含源代码，编码原理
(Huffman coding lab report, containing the source code, coding theory)
- 2011-06-04 20:44:25下载
- 积分：1
