登录
首页 » Visual C++ » basika

basika

于 2012-10-30 发布 文件大小:127KB
0 233
下载积分: 1 下载次数: 2

代码说明:

  经典算法巴斯卡三角的简单实现,vs2010编译通过(Simple implementation of the classic algorithm Pascal triangle, vs2010 compiled by)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • HuffanCoding
    读取数据,统计所得到的文件中每个字母的权值,创建哈夫曼树,哈夫曼编码。哈夫曼解码,解码后内容写入到指定的文件。 读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组,最终可以得到一个存放目标文件内容的数组。 将得到的数组进行字母权值的统计,统计每个字母出现的次数,次数即为每个字母的权值。 将得到的字符数组与权值数组作为创建哈夫曼树的依据,哈夫曼树根据每个字母权值的大小来创建,每个节点,包括权值、父节点、左子、右子和字母本身。 根据哈夫曼树进行编码。形成目标文件的哈夫曼编码,将此编码返回。 根据哈夫曼树得到的数组即为解码数组,解码数组作为解码的结果返回。 写入输出文件,将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入,将数组写入到相应的文件中。 (Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file. Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array. The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter. The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself. According to Huffman coding. The formation of the target file Huffman coding, this code returns. According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)
    2020-07-02 15:40:01下载
    积分:1
  • StackandQueue
    该ppt包含了栈和队列的数据结构及基本操作,同时还有栈的举例(This ppt contains the stack and queue data structure and basic operation, as well as examples of the stack)
    2013-12-06 21:02:24下载
    积分:1
  • chessboard-distance
    一道poj上的问题的解答,棋盘上的距离问题。即实现棋盘上从一个点移动到王,后,兵之间最短步数的解答。(A poj answers to your questions on the chessboard distance problem. That is, move from one point to the king on the board, after the shortest number of steps between the soldiers answer.)
    2012-06-20 10:10:45下载
    积分:1
  • function
    提供字符串方法,大家面试可以用,包括找出对称字串(Some string function)
    2011-05-14 23:14:49下载
    积分:1
  • joseph
    用链表解决约瑟夫问题。 约瑟夫环是一个数学的应用问题:已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。 其中包括一个实验报告,介绍了编程思路和输出结果截图。(List to resolve Joseph. Josephus is the application of a mathematical problem: Given n individuals (numbered 1, 2, 3, ... n, respectively) sitting around a round table around. From number k people began to count off the number to m the man out of the line his next person and from a number off, the man was out of the line number to m so regularly repeated down until roundtable around of the people all of the columns. Including a lab report describes the programming ideas and output screenshots.)
    2012-08-27 22:37:52下载
    积分:1
  • Classic-single-linked-list
    单链表是C经典数据结构算法和数据结构,希望这对大家学习有点用(Classic single-linked list data structure in C algorithms and data structures, which we hope to learn a little bit with)
    2011-08-02 12:33:26下载
    积分:1
  • exp2-1
    数据结构(第四版)第二章上机实验题源程序答案详解(Data structure (fourth edition) chapter on lab answer questions Detailed source)
    2014-12-31 09:14:51下载
    积分:1
  • main5
    编写一个将二叉树的所有叶子结点从左向右链接成单链表的算法(Write a binary tree leaf nodes from left to right links into a single linked list algorithm)
    2012-10-07 23:52:44下载
    积分:1
  • sgu-499
    题意:给你n个数,求出两两组合的最大公约数 类似打素数表的做法 (Meaning of the questions: to give you the number n, find greatest common divisor of a similar combination twenty-two hit the practice table of prime numbers)
    2011-08-30 21:56:59下载
    积分:1
  • GraphTheory
    讲述数据机构的图论部分和程序设计的关系,适合学习算法的同学学习阅读,很不错的一本书。(Graph theory algorithm and programming)
    2013-12-04 20:12:39下载
    积分:1
  • 696516资源总数
  • 106415会员总数
  • 3今日下载