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matlab
该源代码的功能是用matlab来实现链码提取，内含测试图片及所用的算法源代码。(The source code s function is to use matlab to achieve the chain code extraction, containing pictures and used for testing the algorithm source code.)
- 2009-11-27 21:11:10下载
- 积分：1
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SVM
support vector machine （支持向量机）方法是目前分类方法中比较好的一个分类方法，实验证明准确度非常高！(support vector machine (support vector machine) method is a better classification of a classification method, experimental proof of a very high accuracy!)
- 2008-07-19 17:54:23下载
- 积分：1
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qq
说明： system initialisation in matlab
- 2010-04-21 02:03:33下载
- 积分：1
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IIR
无限脉冲响应数字滤波器IIR算法c语言.c文件(Infinite impulse response IIR digital filter algorithm c language)
- 2014-12-22 16:59:52下载
- 积分：1
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npcsma
np-CSMA协议程序：计算实际产生的业务量 ，吞吐量，平均延迟(np-CSMA protocol procedures: calculation of the actual traffic throughput, average delay)
- 2012-10-10 15:44:45下载
- 积分：1
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7阵元Cholesky分解实现代码Cholesky
7阵元Cholesky分解实现代码，FPGA编程的Matlab对应程序，这是一个子函数，使用时对输入矩阵稍加修改即可(7 elements Cholesky decomposition Matlab corresponding program code, FPGA programming, which is a sub-function, use the input matrix can be slightly modified)
- 2020-07-07 12:38:57下载
- 积分：1
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LTE_System_Level_1.4_r570
To solve this instance of the decision problem we must determine whether there is a truth value (TRUE or FALSE) we can assign to each of the variables (x1 through x4) such that the entire expression is TRUE. In this instance, there is such an assignment (x1 = TRUE,x2 = TRUE, x3=TRUE, x4=TRUE), so the answer to this instance is YES. This is one of many possible assignments, with for instance, any set of assignments including x1 = TRUE being sufficient. If there were no such assignment(s), the answer would be NO.
- 2012-04-23 22:00:12下载
- 积分：1
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matlab-code
matlab 的经典解方程组的几个例子，对于解方程会有帮助。(matlab code)
- 2013-04-09 15:31:32下载
- 积分：1
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STEP-Mobility-Model
STEP Mobility Model.
Simulates moving Nodes (position and Velocity in time
- 2012-12-10 18:24:08下载
- 积分：1
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colone-immune-algorithm
克隆免疫算法，将记忆库种群采用克隆算法进行复制(Immune clone algorithm, using cloned populations of memory copy algorithm)
- 2011-09-20 09:26:31下载
- 积分：1
