-
interference_pattern_of_polarize_light
此程序计算了会聚偏振光的干涉图样，其结果对于偏振光的分析有指导作用。(This program calculated convergent polarized light interference pattern, the results of the analysis for the polarized light guide.)
- 2010-03-06 23:24:57下载
- 积分：1
-
pca
PCA主成分分析，是一种常用的基于变量协方差矩 阵对信息进行处理、压缩和抽提的有效方 法。 (PCA principal component analysis, is a common and effective method is based on the covariance matrix of variable information processing, compression and extracted.)
- 2014-09-24 10:38:42下载
- 积分：1
-
book
徐荣桥《结构分析的有限元法与Matlab程序设计》书。(Xu Rong bridge " structural analysis of the finite element method and Matlab programming" book.)
- 2013-10-24 15:55:07下载
- 积分：1
-
zuiyouhua-matlab-homework
最优化课程matlab编程作业，大家下载的时候一定先看清题目要求(zuiyouhua matlab homework)
- 2015-01-11 20:40:36下载
- 积分：1
-
chaper6
机器人控制系统的设计及其matlab仿真第6章“机器人反演控制”源代码(Chapter 6 of the robot control system design and its matlab simulation robot inversion control " source code)
- 2013-04-25 14:24:19下载
- 积分：1
-
net
说明： 有感知器神经网络实现1与0的识别，输出误差曲线(it is a good program!if you needed,be quick to load it down)
- 2010-04-21 16:19:43下载
- 积分：1
-
bezier_surface_display
BEZIER_SURFACE_DISPLAY is a work in progress . I have managed to read the data in and display a crude image, in which each Bezier patch is represented by a flat rectangle. Obviously, I need to take the next step, which is to be able to sample the bicubic function and display a finer mesh of rectangles, in order to see the teapot in its glory!
- 2014-08-14 05:10:10下载
- 积分：1
-
luo_gmm
利用GMM算法，来检测纹理的一个代码！非常有用.(using GMM to detection texture)
- 2010-06-21 14:42:59下载
- 积分：1
-
2
说明： 采用M语言进行卡尔曼滤波器仿真matlab程序(M language Kalman filter simulation)
- 2012-05-25 13:00:13下载
- 积分：1
-
MadHG
利用函数MadHG生成规则LDPC码的校验矩阵H，其行重为6,列重为3,行数为列数一半(行数越大越好)，H中任意两列没有围长为4的圈，并得到H对应的生成矩阵G，可以保证mod(G*H ,2)=0。使用方法为:[H,G] = MadHG(m,n,x),x= 1(得到的G左半部分为单位阵) or 2(G右半部分为单位阵),(use function MadHG Generation rules LDPC check matrix H, re-6, series of three, out for a few half of the number (A bigger the better), H 2 arbitrary no girth of the four circles, H counterparts and with the formation of matrix G, we can be assured of mod (G* H, 2) = 0. To be used : [H, G] = MadHG (m, n, x), x = 1 (the G part of the Left Front units) or 2 (G right half of the units RUF),)
- 2007-05-12 10:54:46下载
- 积分：1
|
联系客服（QQ：3324461878）
