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算法设计与分析基础的课后习题答案,潘彦著,清华大学出版...
算法设计与分析基础的课后习题答案,潘彦著,清华大学出版-Algorithm design and analysis of the basic answer to after-school exercise, the PAN Yan, Tsinghua University Publishing
- 2022-05-28 22:33:38下载
- 积分:1
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节点互斥的ASP.NET TreeView动态树形菜单
节点互斥的ASP.NET TreeView动态树形菜单,N年前写的了,扔了这么多年重新扒出来了,当时在VS2003下测试通过
1。工具箱-->添加/移除项-->选.NET组件--浏览--打开--确定
2。把Microsoft.Web.UI.WebControls.dll复制到BIN文件夹中,添加引用
3。由工具箱拖放TREEVIEW控件
4.前台ShowPlus="False" ShowLines="False"控件显示格式
5.JS脚本控制节点互斥
- 2023-05-30 02:35:03下载
- 积分:1
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chaoliuchengxu
通用型潮流程序,供电力系统分析初学者借鉴(matlab )
- 2020-12-01 22:19:26下载
- 积分:1
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Leader-follower_OK
基于MSRDS领航跟随法多机器人编队控制SPL代码(Based on MSRDS pilot to follow the method of multi-robot formation control SPL code)
- 2021-02-09 19:49:53下载
- 积分:1
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Test
使用python实现的运行推荐算法的脚本文件(A test demo to run recomandation system)
- 2019-04-28 11:03:11下载
- 积分:1
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NSGA-2
说明: NSGA-2算法的C++实现,包含头文件(C + + implementation of nsga-2 algorithm)
- 2019-11-09 10:36:46下载
- 积分:1
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EMD_Toolboxs
说明: 经验模态分解,求取本征模IMF,用于求解函数或者输出响应的时域分解,与FFt和小波分析不同,具有独特的优势。(Empirical mode decomposition (EMD) is used to solve the time domain decomposition of function or output response, which is different from FFT and wavelet analysis.)
- 2020-07-09 15:58:06下载
- 积分:1
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839960162ADCs_DMA
两路ADC+DMA,stm32f103,双通道采集(ADC+DMA,stm32f103,2adc)
- 2019-06-24 15:21:07下载
- 积分:1
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ck
说明: 本地直接播放! 可控制 快进全屏功能都有(Local direct play! Controllable fast-forward full-screen features are available)
- 2019-08-17 19:36:02下载
- 积分:1
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本算法使用分治法求解最近点对问题。事先用O(nlogn)时间对x坐标进行排序,使得所有的点是按x坐标从小到大排好序的(x坐标相同时y坐标小的排前),然后取下标小...
本算法使用分治法求解最近点对问题。事先用O(nlogn)时间对x坐标进行排序,使得所有的点是按x坐标从小到大排好序的(x坐标相同时y坐标小的排前),然后取下标小于n/2属于左边的点集PL,取下标大于n/2属于右边的点集PR,即用O(1)时间就可以将规模为n的问题分解为两个规模为n/2的、同类型的子问题。分割完毕之后就可以采用分治法,分别求出PL和PR中的最近点对,最终通过递归实现。-This algorithm uses divide and conquer to solve the problem closest point. Prior to use O (nlogn) time to sort the x coordinate so that all points are based on x coordinates from small to large sorted (x coordinates with the same y coordinates of the small, the top), and then remove the standard is less than n/2 the set of points belonging to the left PL, remove the standard is greater than n/2 set of points belonging to the right of PR, that is to use O (1) time can be the problem size n divided into two size n/2, the same type The sub-problems. Segmentation can be used after completion of sub-rule method, respectively, find the PL and PR in the last points and eventually through the recursion.
- 2022-01-25 16:01:13下载
- 积分:1