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xinhao
1 设计一个ＦＩＲ数字低通滤波器， 满足一组模拟滤波器的指标参数；分别采用三角窗、hamming窗、blackman窗和kaiser窗进行设计。比较不同窗的设计效果。要求描绘滤波器的脉冲响应、窗函数以及滤波器的幅频和相频响应曲线。
2. 用上述设计滤波器完成几组给定信号的滤波。
3.设计数字高通、带通、带阻滤波器，要求描绘滤波器的脉冲响应以及滤波器的幅频和相频响应曲线。
(1、A design of a FIR digital low-pass filter, analog filters to meet the target of a group of parameters were used triangular window, hamming window, blackman windows and kaiser window design. Window to compare different design effect. Requirements described impulse response filter, window function and the filter amplitude-frequency and phase frequency response curve.
2. Using the above filter was designed to complete several sets of a given signal filtering.
3. Design of digital high-pass, band pass, band-reject filter, the filter impulse response described demand as well as the filter amplitude-frequency and phase frequency response curve.)
- 2010-01-10 19:54:03下载
- 积分：1
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qpsk_rayl
qpsk信号瑞利信道的仿真程序还有搞死的有ber(qpsk signal Rayleigh channel simulation program has also Gaosi ber)
- 2013-11-14 13:03:27下载
- 积分：1
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Set-invariance-in-control
positively invariant
sets and their application to the analysis and synthesis of control systems.
- 2013-10-23 20:05:59下载
- 积分：1
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smith-
matlab编写的史密斯圆图
运行.m文件(matlab Smith prepared plans to run. m file)
- 2007-07-15 01:45:49下载
- 积分：1
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simulink_question
学习MATLAB的simulink工具箱时会经常遇到的问题，很好很受用，肯定对初学者有帮助。(MATLAB-simulink toolbox learning problems often encountered when, well popular with, certainly helpful for beginners.)
- 2010-09-09 21:56:45下载
- 积分：1
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beamforming
With the interference-to-noise ratio reduced to 30 dB, plot the adaptive antenna pattern after 200 iterations of the LMS algorithm(With the interference-to-noise ratio of red uced to 30 dB. plot the adaptive antenna pattern after 200 ite rations of the LMS algorithm)
- 2006-11-04 23:39:40下载
- 积分：1
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ZF_LF_BER
多小区MIMO系统ZF和LF预编码方案的性能比较(Multi-cell MIMO system ZF and LF Performance Comparison of pre-coding scheme)
- 2011-05-28 14:55:01下载
- 积分：1
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Code
image classification using SVM
- 2013-12-02 11:09:13下载
- 积分：1
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ForK1
我们的目的是将一个分数拆分成若干个分子是1分母是正整数的分数之和的形式。例如2/3可以拆分成1/2+1/6的形式。这里不考虑顺序，比如1/6+1/2和1/2+1/6相同。
输入p, q, a, n, 其中p/q为分数，对这个分数进行拆分，要求拆分的分数个数不能多于n个，所有分母的乘积不能大于a。求有多少种拆分方法?
输入：最多200组数据。在每行中都有四个数分别表示p, q, a, n，之间以空格隔开，并且满足p,q<=800，a<=12000，n<=7，最后以四个0做为输入的结束。
输入示例:
2 3 120 3
2 3 300 3
0 0 0 0
输出示例:
4
7
(Our aim is to split a fraction into a number of elements is a denominator is a positive integer fraction of the sum of form. For example, 2/3 can be split into 1/2+1/6 form. Not considered here, the order, such as 1/6+1/2 and 1/2+1/6 of the same. Input p, q, a, n, where p/q as a fraction of this split scores require no more than the number of split points n-all the product of the denominator can not be larger than a. How many kinds of demand split method? Input: Up to 200 sets of data. In each line has four numbers indicate the p, q, a, n, separated by a space between, and meet the p, q < = 800, a < = 12000, n < = 7, the end, four 0 as the input end. Input Example: 2,312,032,330,030,000 sample output: 47)
- 2009-11-12 09:54:17下载
- 积分：1
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ALG024
SECANT法求解一个连续方程，f(x) = 0，给两个初始值( SECANT ALGORITHM 2.4
To find a solution to the equation f(x) = 0
given initial approximations p0 and p1:
INPUT: initial approximation p0, p1 tolerance TOL
maximum number of iterations N0.
OUTPUT: approximate solution p or
a message that the algorithm fails.)
- 2009-04-30 21:39:11下载
- 积分：1
