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riskgranger

于 2016-09-07 发布文件大小:71KB

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下载积分: 1 下载次数: 3

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代码说明：

risk Granger 因果关系检验模型(risk Granger)

文件列表：

riskgranger
...........\aorisk_granger.mat,612,2015-04-24
...........\axy.m,385,2015-04-26
...........\bp0214risk_granger.mat,490,2015-04-24
...........\bprisk_granger.mat,1066,2015-04-24
...........\c2t.m,169,2015-04-24
...........\corrxy.m,350,2015-04-26
...........\cov(j,,0,2015-04-25
...........\cross_corr_error.m,2074,2014-02-12
...........\ct.m,100,2015-04-24
...........\d2t.m,193,2015-04-24
...........\dgrisk_granger.mat,594,2015-04-25
...........\dt.m,112,2015-04-24
...........\fgrisk_granger.mat,603,2015-04-25
...........\granger.m,457,2016-04-26
...........\hgrisk_granger.mat,560,2015-04-25
...........\hkrisk_granger.mat,609,2015-04-25
...........\q1t.m,320,2015-04-26
...........\q22t.m,338,2015-04-25
...........\q2t.m,632,2015-04-26
...........\qt.m,314,2015-04-26
...........\rbrisk_granger.mat,1004,2015-04-25
...........\risk_granger.mat,46176,2015-04-24
...........\szrisk_granger.mat,568,2015-04-26
...........\twrisk_granger.mat,971,2015-04-25
...........\ydrisk_granger.mat,587,2015-04-25
...........\ygrisk_granger.mat,593,2015-04-25
__MACOSX
........\riskgranger
........\...........\._cov(j,,11339,2015-04-25
........\...........\._granger.m,120,2016-04-26

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lorenz0110
这是一个混沌理论中重要的Lorenz映射的程序。通过曲线很容易看到奇妙的混沌现象(Chaos Theory important Lorenz mapping procedures. Curve it is easy to see the amazing phenomenon of Chaos)

2007-03-07 20:02:20下载

积分：1
denoisingWavelet
Wavelet denoising For using this code need to use signal toolbox and general toolbox in your matlab In the first part of this assignment, we asked to obtain a (black-and-white) digital image of size 512 by 512 and then generate noisy image by adding a Gaussian noise but under the condition of having SNR=20dB by select the suitable value of variance for Gaussian noise formula. Second step is performing wavelet denoising using the hard thresholding (Use the db 6 for four levels) in the condition of finding the optimal thresholding value of T in terms of the SNR obtained. It means that, we should find the highest SNR value by finding the suitable value for threshold. Then we asked to do the same process but this time using soft thresholding. Finally for the last part of question one, we should compare the results of the obtained SNR with the recommendations of 3*sigma for the hard thresholding and 3/2*sigma for the soft thresholding.

2013-12-11 17:34:39下载

积分：1
PSOt
Particle Swarm Optimization

2015-04-09 10:32:51下载

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BL
所建立的无刷直流电动机系统的Simulink仿真模型图，功能模块包括：逆变器模块、电源模块、换相逻辑模块、PWM信号产生模块、电动机本体模块、转速测量模块和磁极位置测量模块。(Established by the brushless DC motor system Simulink simulation model, and functional modules including: inverter module, power module, commutation logic, PWM signal generation module, motor body module, measuring module and the pole position speed measurement modules.)

2010-05-10 08:54:22下载

积分：1
Plate
车牌定位Matlab程序，可以实现汽车车牌的定位。(License plate location Matlab program, you can achieve the positioning of vehicle license plates.)

2015-02-06 11:49:19下载

积分：1
ACTIVE-CLAMP-FLYBACK-FORWARD-CONVERTER
GENERAL POWER ELECTRONICS SIMULIK MODELS

2014-01-04 17:00:07下载

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test
一个简单的水平集演化的matlab仿真，带注释。便于初学matlab，图像处理以及水平集的同学学习。(A simple level set matlab simulation, with comments. Easy beginner matlab, image processing and level set of students to learn.)

2010-06-05 19:04:44下载

积分：1
amicmi.rar
进入MatLab程序运行界面后，运行程序，界面会出现请输入NRZ玛，输入方式按数组方式输入，确认输入的NRZ码之后，程序会自动输出 CMI，AMI，HDB3的编码和解码的结果，可以清晰的对照出编码前后的结果。(into MatLab interface operating procedures, operating procedures, the interface will enter emerging NRZ Mary, by the array input mode input and confirm the NRZ, the program will automatically output CMI, AMI, HDB3 encoding and decoding, the results of which will clear up the control of the results before and after encoding.)

2007-06-02 16:53:46下载

积分：1
linechirp_normal
matlab 实现啁啾光栅的反射谱计算没有切趾函数普通的线性啁啾反射谱(matlab calcuated the refrective spectrum of linear chirped grating .)

2013-12-05 11:03:21下载

积分：1
rank_corr
利用数据拟合概率密度函数建立可靠度分析所需的概率分布函数(There is one outlier in the data of , but is not of data .For and the line of Q2 is in the middle of the box, so there are not asymmetries for both and .)

2011-06-20 17:49:53下载

积分：1

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