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DSLComputePath
D star 搜索算法,从目标节点向起始点搜索,机器人沿最短路径开始移动,机器人路径规划探路的一种算法(D star search algorithm, from the target node to the starting point search, the robot moves along the shortest path, the robot path planning Pathfinder algorithm)
- 2017-10-25 10:02:50下载
- 积分:1
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stm32isp.tar
linux 下载 stm32 程序,更改boot引脚和复位引脚直接使用。(Linux downloads the STM32 program)
- 2018-06-13 17:49:18下载
- 积分:1
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电子语言,最新的自动更新的源代码,实现主…
易语言的最新自动更新的源码,实现了主程序和非主程序的自动更新.-E language, the latest automatic updates of the source code to achieve the main program and non-automatic updates of the main program.
- 2022-02-25 09:11:10下载
- 积分:1
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C#获取Windows属性信息
C#获取Windows属性信息,比如获得Windows用户名、操作系统版本、计算机名、Windows版本号、Windows启动方式、网络是否连接、显示器数量及分辨率等信息。
- 2022-07-25 10:47:16下载
- 积分:1
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制作的预加载动画特效。
一组使用纯CSS3制作的预加载动画特效。这组CSS3预加载动画特效共有(The hor effect of this group of pictures has 16 special effects. The effect also supports the rap version.)
- 2019-02-13 11:11:37下载
- 积分:1
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CapsNet-Tensorflow-master
说明: 2017年10月,图灵奖得主Geoffrey Hinton在机器学习的顶级会议“神经信息处理系统大会(NIPS)”上发表了题为《胶囊之间的动态路由》(Dynamic Routine Between Capsules)的论文,提出了全新的深度学习方法——胶囊网络(In October 2017, Turing prize winner Geoffrey Hinton published a paper entitled "dynamic routing between capsules" at the top conference of machine learning "nips", and proposed a new deep learning method capsule network)
- 2020-07-18 22:08:02下载
- 积分:1
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跳转到QQ聊天类库
说明: 跳转到QQ聊天类库 易语言编写 JSON操作类库,个人测试使用,完整类库(Jump to QQ Chat Library)
- 2019-01-05 08:48:41下载
- 积分:1
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chanpinzhiliang
通达OA工作流中产品质量检查报告流程设计(Mastery OA workflow product quality inspection report process design)
- 2009-01-20 15:57:27下载
- 积分:1
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数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的...
数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的根。
输入:
输入有多个案例。每一个案例为一行,每行只有一个整数N。当输入的N是-1时,输入结束。
输出:
每一个案例输出一行。每行只有一个数字,就是N对应的数根。
Sample input
39
-1
Sample output
3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3
- 2023-09-05 21:25:03下载
- 积分:1
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1插值法—拉格朗日插值法
使用matlab编写了拉格朗日插值算法的函数,里面有题目,可直接运行计算得到结果。(The function of Lagrange interpolation algorithm is written by MATLAB. There are questions in it, which can be directly run and calculated and get the result.)
- 2020-12-21 21:29:07下载
- 积分:1