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使用函数实现简单的八位处理器
软件开发环境：ISE 7.1i
仿真环境：ISE Simulator
1. 这个实例实现通过ISE Si...
使用函数实现简单的八位处理器
软件开发环境：ISE 7.1i
仿真环境：ISE Simulator
1. 这个实例实现通过ISE Simulator工具实现一个可以进行两个八位操作数四种操作的简单处理器；
2. 工程在project文件夹中，双击mpc.ise文件打开工程；
3. 源文件在rtl文件夹中，mpc.v为设计文件，mpc_tb.tbw是仿真波形文件；
4. 打开工程后，在工程浏览器中选择mpc_tb.tbw，在Process View中双击“Simulation Behavioral Model”选项，进行行为仿真，即可得到仿真结果。-The use of a simple function to achieve the eight-processor software development environment: ISE 7.1i simulation environment: ISE Simulator 1. This example through the ISE Simulator tool to achieve the realization of a two operand four of eight simple processor operation 2. works in the project folder, double-click to open the project file mpc.ise 3. rtl source file in the folder, mpc.v documents for the design, mpc_tb.tbw is the simulation waveform files 4. to open a project, a browser in the works Select device mpc_tb.tbw, double-click in the Process View in the " Simulation Behavioral Model" option, to carry out acts of simulation, simulation results can be obtained.
- 2023-03-17 12:55:03下载
- 积分：1
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threads on the process used vc viewer's own Process Viewer and think that th...
关于进程&线程查看器 用过vc++自带的Process Viewer，觉得这个小程序简单易用，有时候作用还很大，我就产生了自己做一个类似程序的想法，想着想着就着手作了起来。 首先我查看了有关进程和线程的api函数（在tlhelp32.h中）了解了他们的用法。 具体实施阶段: 界面设计：该实用程序的界面几乎完全参考vc++自带的Process Viewer，以前从未接触-threads on the process used vc viewer"s own Process Viewer and think that this small program is easy to use, has great role Sometimes, I have done a similar proceedings to the idea of embarking on pondered made up. First I look at the relevant processes and threads api function (in tlhelp32.h) understanding of their usage. Specific implementation phase : interface design : The utility interface reference vc almost entirely onboard Process Viewer, never contacts
- 2022-03-22 05:20:03下载
- 积分：1
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这是一个使用c++语言编写的斗地主小游戏。在游戏的AI上花费了不少时间，是一个值得研究的经典例子...
这是一个使用c++语言编写的斗地主小游戏。在游戏的AI上花费了不少时间，是一个值得研究的经典例子-This is a use of c++ language written in Doude Zhu game. The AI in the game spend a lot of time, is a classic example is worth studying
- 2022-02-09 11:40:52下载
- 积分：1
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The explain of C4.5 document(data type,run environment)
C4.5文档说明（数据类型，运行环境）-The explain of C4.5 document(data type,run environment)
- 2022-07-05 10:27:10下载
- 积分：1
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Find prime numbers prepared by screening the function: void sieve (bool isPrime...
编写筛选查找素数函数：
void sieve(bool isPrime[], int n)
其中isPrime[ ]为一个布尔型数组，n为数组大小。由于2是第一个素数，
所以设置isPrime[0]和isPrime[1]的值为false，并设置其余的元素初值为true。
然后对从4到n－1的每一个i，判断i是否能够被2整除，如果i能够被2整除，则设置isPrime[i]为false。
对从2到n/2的每一个可能的数值重复以上处理，当操作结束时，所有值为true的isPrime[i]所对应的i就是素数，它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.
- 2023-03-02 04:45:03下载
- 积分：1
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很不错的结合DateTime的综合例子
很不错的结合DateTime的综合例子-very good combination DateTime the comprehensive example
- 2023-08-16 04:30:04下载
- 积分：1
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（本文是在论坛已有一篇文章《SIRP法相干相关K分布雷达杂波的建模与仿真》的基础上修改而来，在此首先感谢这篇文章的作者给予我的帮助。之所以完成这篇文章，有三个方...
（本文是在论坛已有一篇文章《SIRP法相干相关K分布雷达杂波的建模与仿真》的基础上修改而来，在此首先感谢这篇文章的作者给予我的帮助。之所以完成这篇文章，有三个方面的原因：一是对原文章和仿真程序代码明显存在一些不一致的地方，因此，我这里对每个公式进行检验（后来证明文章的公式正确无误，但所给的仿真代码存在问题），二是对自己近4天工作的一个总结，以便以后学习可以参考；三是可以放在网上给初学者一些参考，以便后来者不再走自己曾经走过的弯路。文章的一些文字是在匆忙间完成，只求能表达所述意思，没有详细斟酌，海涵：-(This article is an article in the forum have been "SIRP law related coherent K distributed clutter radar modeling and simulation" on modified from the foundation, in this first of all thank the authors of this article has given me help. The reason why the completion of this articles, there are three reasons: First, the original article and simulation program code, there are some obvious inconsistencies, so I here the formula for each test (later proven formula article is correct, but give the simulation code problem exist), near two of their four days of a summary of the job in order to study the future reference three on-line can give some reference for beginners in order to go was no longer the tortuous path they have traversed. arti
- 2022-06-17 14:10:51下载
- 积分：1
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有关CAD/CAM的资料,希望对大家有帮助
有关CAD/CAM的资料,希望对大家有帮助-Related to CAD/CAM data, and they hope to have everyone help
- 2022-06-29 14:45:01下载
- 积分：1
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java 说明.下载到受机中不要在电脑中解压
java 说明.下载到受机中不要在电脑中解压-java notes. downloaded to the affected machine will not unzip on your computer
- 2022-11-30 19:40:08下载
- 积分：1
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本源码是用封闭的LabVIEW仿真直流电机
本源码是用labview仿真直流电机闭环控制的程序，希望对大家有用-The source is a DC motor using LabVIEW Simulation of closed-loop control procedures, in the hope that useful to everybody
- 2022-02-13 19:41:16下载
- 积分：1
