-
在CCS开发环境下利用DSP怎样运行一个程序！
在CCS开发环境下用DSP芯片怎样运行一个程序！-in CCS development environment using DSP how you run a procedure!
- 2022-01-26 05:49:10下载
- 积分：1
-
简单的DOS命令
ping，arp等，无聊时候做的
简单的DOS命令
ping，arp等，无聊时候做的-Simple DOS command ping, arp, etc. do when bored. . .
- 2022-06-18 22:31:48下载
- 积分：1
-
LU matrix decomposition, this decomposition can solve the equations
矩阵的LU分解,通过此分解可以求解方程组-LU matrix decomposition, this decomposition can solve the equations
- 2022-05-07 16:59:28下载
- 积分：1
-
支持以下啊,java代码
感谢 不尽啊
支持以下啊,java代码
感谢 不尽啊 -support the following ah, java code Boundless thanks ah
- 2022-03-24 12:08:49下载
- 积分：1
-
大一时写的一个人事课设，写的不好，就看看而已
大一时写的一个人事课设，写的不好，就看看而已-large write a lesson based personnel and write well, only to see it
- 2023-04-01 14:25:04下载
- 积分：1
-
计算一个非负整数矩阵的铪质。注：复制铪质。C的方法。
Computes the hafnian of a nonnegative integer matrix. Notes: Copy hafnian.c to main.c, in the same directory as Rothberg s code (see above). You can download the .tar directory with the code weighted-match.tar here. Then "make" the codes (this codes are in C, not C++). The program is then run by the command "wmatch". -Computes the hafnian of a nonnegative inte ger matrix. Notes : Copy hafnian.c to main.c, in the same directory as Rothberg"s code (see abo ve). You can download the. tar directory with th e code weighted-match.tar here. Then "make" th e codes (this codes are in C, not C). The program is then run by the command "wm atch. "
- 2022-01-30 19:38:32下载
- 积分：1
-
现在广被认可的NCIE考试的相关类容！有兴趣的可以
现在广被认可的NCIE考试的相关类容！有兴趣的可以-now widely recognized NCIE examination-related capacity! Interested parties can s
- 2022-02-03 03:10:27下载
- 积分：1
-
采用VC6.0实现了遗传算法，并且具有一定的通用性，实现一般的运用...
采用VC6.0实现了遗传算法，并且具有一定的通用性，实现一般的运用-VC6.0 achieved using genetic algorithms, and have a certain commonality to achieve general use
- 2023-04-29 04:10:03下载
- 积分：1
-
Neusoft embedded programming training, quality is very good, well
东软嵌入式编程培训,质量非常不错,著名公司的质料,对编程非常有帮助-Neusoft embedded programming training, quality is very good, well-known companies of the material, on the programming very helpful
- 2022-10-10 10:40:04下载
- 积分：1
-
某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下：
每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和...
某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下：
每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。-A company to transfer data using public telephones, the data is four integers, in the transmission process is encrypted, encryption rules are as follows: Each figures with five, and then divided by 10 instead of the more than a few numbers, and then The first and fourth exchange, the second and third exchange.
- 2022-01-26 00:00:43下载
- 积分：1
