-
开发语言: Java 运行平台: LINUX/UNIX Windows 2000 精彩不容错过
开发语言: Java 运行平台: LINUX/UNIX Windows 2000 精彩不容错过-development languages : Java platforms : Linux/UNIX Windows 2000 wonderful not to be missed
- 2022-03-13 22:24:39下载
- 积分：1
-
很好的源码，能构监听网络数据包，也是学习VC++得很好的源码...
很好的源码，能构监听网络数据包，也是学习VC++得很好的源码-Very good source that can monitor network packets conformation is also studying VC++ very good source
- 2022-02-03 00:18:41下载
- 积分：1
-
with VC6 development of the single
用VC6开发的单文档程序,在程序启动时检测是否连接到网络上,并用对话框提示.将此功能封装成了函数,具体见代码.-with VC6 development of the single-file procedures, the commencement of proceedings test for connecting to the network, and the dialog box prompt. Packaging has become functional this function, see specific code.
- 2022-05-08 14:21:30下载
- 积分：1
-
This is one the students have done, not doing a good job, I hope everyone with r...
这是一同学做得，做得不好，希望大家一起参考参考。具体在压缩包里有详细介绍-This is one the students have done, not doing a good job, I hope everyone with reference to reference. Concrete in the compression bag detailed
- 2022-06-12 12:20:18下载
- 积分：1
-
一个控制台的select模型的聊天服务器
一个控制台的select模型的聊天服务器-console select a chat server model
- 2023-03-28 14:35:04下载
- 积分：1
-
自己看中，一个ＰＨＰ程序，ＰＨＰ版的，哈哈哈，还比较好用的...
自己看中，一个ＰＨＰ程序，ＰＨＰ版的，哈哈哈，还比较好用的-own case, a procedure PHP, PHP version of the conversations, but also better quality
- 2022-04-28 02:48:34下载
- 积分：1
-
一个简单的IOCP网络模型，VC6编译通过
一个简单的IOCP网络模型，VC6编译通过-A simple IOCP network model, VC6 compiled by
- 2023-01-10 13:55:03下载
- 积分：1
-
一个高效的tcp端口扫描器
一个高效的tcp端口扫描器- A highly effective tcp port scanner
- 2022-01-31 01:16:32下载
- 积分：1
-
初学者入门的好教材，linux下的c/s围棋程序
初学者入门的好教材，linux下的c/s围棋程序-good material, linux under the c/s Go procedures
- 2022-02-13 05:17:57下载
- 积分：1
-
unsustainable under the agreement, users send frames, will first interception Ch...
非持续CSMA
该协议下，用户在发送帧之前，会先侦听信道的状况，如果没有其他站点发送，它就发送。若信道忙，它就等待一个随机的时间后重复以上动作。
对于某一帧而言，信道是否忙，即是看其绝对时间（FRAMETIME*i+dt）的前一帧时内（FRAMETIME*(i-1)+dt ~ FRAMETIME*i+dt）是否存在发送帧。若无则发送，有则等待一随机时间。
-unsustainable under the agreement, users send frames, will first interception Channel situation, if no other site sent, it sent. If Channel busy, it would wait for a random time to repeat the action. For a frame, whether the busy channel, that is, look at his absolute time (FRAMETIME* i dt) of a time (FRAMETIME* (i-1) dt ~ FRAMETIME dt* i) the existence of this frame. If not then this, then wait for a random time.
- 2022-03-16 02:26:57下载
- 积分：1
