-
分形算法和程序设计2章，用的是C语言程序设计
分形算法与程序设计 第2章VC语言程序设计-Fractal Algorithms and Program Design Chapter 2 VC Language Program Design
- 2022-10-04 01:05:03下载
- 积分：1
-
this is a FFT algorith using by matlab code
this a FFT algorith using by matlab code-this is a FFT algorith using by matlab code
- 2023-03-25 16:05:03下载
- 积分：1
-
约瑟夫问题。有N个人围成一圈，按顺序编号。从第一个人开始报数，疏导m时候该人退出，并且下一个从1开始报数。求出圈人的顺序。...
约瑟夫问题。有N个人围成一圈，按顺序编号。从第一个人开始报数，疏导m时候该人退出，并且下一个从1开始报数。求出圈人的顺序。-Joseph problems. There are N individuals and form a circle, according to sequentially numbered. Starting from the first person reported that the number of times to ease the person out of m, and the next one starting from a newspaper a few. Find the circle of people order.
- 2022-08-15 13:00:55下载
- 积分：1
-
三维电阻率正演模拟软件！！！加工。有限差分法
电阻率3D正演软件！！！用有限差分方法编写-3D resistivity forward modeling software! ! ! The finite difference method to prepare
- 2023-07-20 00:55:05下载
- 积分：1
-
128位长双精度型数字运算包
128位长双精度型数字运算包-128 long double precision numeral operation package
- 2022-06-16 16:49:03下载
- 积分：1
-
摄影测量中将数据读入，进行空间外方位元素的计算和控制测量点的确定...
摄影测量中将数据读入，进行空间外方位元素的计算和控制测量点的确定-Photogrammetry data will be read, space orientation element of calculation and measurement control points identified
- 2022-09-24 22:05:02下载
- 积分：1
-
常用的数学统计算法，希望大家喜欢
Calculate the approximation of the standard normal distributi...
常用的数学统计算法，希望大家喜欢
Calculate the approximation of the standard normal distribution
-commonly used mathematical statistical algorithm, hope you like Calculate the approximation of the stan DST normal distribution
- 2022-05-08 07:44:15下载
- 积分：1
-
C4.5 is a simplified version of the Decision Tree Algorithm
C4.5的简化版本是一个决策树的算法-C4.5 is a simplified version of the Decision Tree Algorithm
- 2022-01-22 07:48:49下载
- 积分：1
-
Ordinary and Partial Differential Equation Routines in C, C++, Fortran, Java, Ma...
Ordinary and Partial Differential Equation Routines in C, C++, Fortran, Java, Maple, and MATLAB
- 2022-03-20 04:40:00下载
- 积分：1
-
百钱买百鸡算法设计和分析
应用背景方法一：伪代码输入：n只鸡的个数 输出：公鸡、母鸡和小鸡的个数1、初始化解的个数count=0； 2、循坏变量从x从0~n/5（取整）; 2.1循环变量y从0~n/3(取整)； 2.1.1 循环变量z从0~n； 2.1.2 如果5*x+3*y+z/3==n && x+y+z==n，则count++；输出x、y、z的值； 2.1.3 y++；
- 2022-03-20 10:38:58下载
- 积分：1
