-
Arduino 试验
Arduino 的测试。他们是一个小的例子，我用我测试 arduino 的第一天。也许对你有用。它正在试图控制机器人未来 ！！！
- 2023-04-22 13:25:04下载
- 积分：1
-
自己在初学VB时写的有关Label控件的小例子，本人也是菜鸟，不过欢迎初学者下载
自己在初学VB时写的有关Label控件的小例子，本人也是菜鸟，不过欢迎初学者下载-Their own learning when written in VB on the Label control small example, and I was a rookie, but welcome beginners Download
- 2022-10-02 16:35:02下载
- 积分：1
-
[输入]
图的顶点个数N，图中顶点之间的关系及起点A和终点B
[输出]
若A到B无路径，则输出“There is no path” 否则输出A到B路...
[输入]
图的顶点个数N，图中顶点之间的关系及起点A和终点B
[输出]
若A到B无路径，则输出“There is no path” 否则输出A到B路径上个顶点
[存储结构]
图采用邻接矩阵的方式存储。
[算法的基本思想]
采用广度优先搜索的方法，从顶点A开始，依次访问与A邻接的顶点VA1,VA2,...,VAK, 访问遍之后,若没有访问B，则继续访问与VA1邻接的顶点VA11,VA12,...,VA1M，再访问与VA2邻接顶点...，如此下去，直至找到B，最先到达B点的路径，一定是边数最少的路径。实现时采用队列记录被访问过的顶点。每次访问与队头顶点相邻接的顶点，然后将队头顶点从队列中删去。若队空，则说明到不存在通路。在访问顶点过程中，每次把当前顶点的序号作为与其邻接的未访问的顶点的前驱顶点记录下来，以便输出时回溯。
#include
int number //队列类型
typedef struct{
int q[20]
-[imported] map of the number of vertices N, Vertex map of the relationship between the starting point and end point A and B [output] if A to B without path then exporting "There is no path" Otherwise output A to B on the path vertices [storage structure] plan adopted adjacency matrix of storage. [Algorithm for the basic idea] BFS way from the vertex A, A visit followed with adjacent vertices VA1, VA2 ,..., VAK, visiting times, if not visit B, continue to visit with the VA1 adjacent vertices VA11, VA12 ,..., VA1M. VA2 and then
- 2022-01-25 22:50:29下载
- 积分：1
-
专门清除电脑的顽固代码.很好用.可以更新哦.___pine20060730
专门清除电脑的顽固代码.很好用.可以更新哦.___pine20060730-specialized remove stubborn code. Very good use. Update oh. ___pine20060730
- 2023-08-03 11:10:03下载
- 积分：1
-
简单的原代码统计
简单的原代码统计-simple statistics of the original code
- 2022-03-18 01:12:22下载
- 积分：1
-
这个做的是模拟银行的ATM截面，很简单的一个小程序，大家参考以下把...
这个做的是模拟银行的ATM截面，很简单的一个小程序，大家参考以下把-do is the bank"s ATM simulation section, a very simple one small procedure, we put reference to the following
- 2022-01-21 05:04:12下载
- 积分：1
-
一个归并排序的程序
一个归并排序的程序-sort of a merging process
- 2023-08-16 08:15:03下载
- 积分：1
-
使用LabVIEW实现Modbus CRC计算
利用LabVIEW语言实现MODBUS协议中CRC校验-use LabVIEW to accomplish the CRC calculate in MODBUS
- 2022-02-25 18:32:08下载
- 积分：1
-
Maze Find a path through the maze to any space character in the perimeter of the...
走迷宫 Find a path through the maze to any space character in the perimeter of the maze. Paths through the maze are denoted by a space character and walls by any other non white-space character (apart from . characters). -Maze Find a path through the maze to any space character in the perimeter of the maze. Paths through the maze are denoted by a space character and walls by any other non white-space character (apart from. Characters).
- 2022-12-29 19:05:03下载
- 积分：1
-
闻亭视频通信模块（vcm_dm642）技术参考，版本：V1的…
闻亭公司视频通信模块（VCM_DM642）技术参考资料,版本号：V1.0.详细介绍了这块板子的硬件配置情况,对入门很有帮助.-Wintech Video Communication Module (VCM_DM642) Technical Reference, version: V1.0. Detailed information on the hardware configuration of this board, the on entry helpful.
- 2022-02-01 11:17:34下载
- 积分：1
