-
这是一个wxWidgets为最新版本的2.8.10 Windwos平台,这是技术。
这是wxWidgets for Windwos Platform的最新版本2.8.10,即通常的wxMSW2.8.10。-This is a wxWidgets for Windwos Platform of the latest version 2.8.10, that is the usual wxMSW2.8.10.
- 2022-02-25 16:33:15下载
- 积分:1
-
在WINDOWS CE系统上EVC开发的XP按钮的源码
在WINDOWS CE系统上EVC开发的XP按钮的源码 -in Windows CE system EVC development of XP button FOSS
- 2022-01-26 06:31:00下载
- 积分:1
-
USB上位机程序,非常好的界面,基于MFC的开发,很适合初学者开发...
USB上位机程序,非常好的界面,基于MFC的开发,很适合初学者开发-USB host computer program, a very good interface, the MFC-based development, it is suitable for beginners to develop
- 2022-03-06 20:31:56下载
- 积分:1
-
双人战斗游戏,游戏虽小,却是研究游戏制作的易懂源码
双人战斗游戏,游戏虽小,却是研究游戏制作的易懂源码-Double fighting games, the game is small, but the game is to study the production of easy-to-understand source
- 2022-05-29 13:59:26下载
- 积分:1
-
用于实现JAVA树结构的BEAN
用于实现JAVA树结构的BEAN-used to achieve the tree structure of the Java Beans
- 2022-02-04 01:53:14下载
- 积分:1
-
模仿窗口用户界面程序
模仿WindowsXP用户接口的程序-imitate the Windows user interface procedures
- 2022-06-03 20:22:20下载
- 积分:1
-
CrossTheMaze
Assume that Edison has found himself in a square-shaped maze of NxN square cells which is surrounded by walls from the outside. In the maze, some of the cells are also walls. Edison can only move between two empty cells in four directions, north, south, west and east. In order to get out of the maze, he drafts a plan. He uses his left hand to lean on the wall and goes by following the wall.
Here is the question, is Edison able to get out of the maze in at most 10,000 steps? If he can make it, output the path. By getting out of the maze, he only needs to be in the exit cell. If the starting cell is the same as the exit, Edison won"t need to move and can directly get out of the maze.
Input
The first line of the input gives the number of test cases, T. T test cases follow. Each test case starts with an integer N. N is the size of the maze. Th
- 2022-02-25 06:08:30下载
- 积分:1
-
包含求反余弦函数,计算Y/X的反正切值 ,向上舍入,把一个双精度数分解为尾数的指数,计算直角三角形的斜边长...
包含求反余弦函数,计算Y/X的反正切值 ,向上舍入,把一个双精度数分解为尾数的指数,计算直角三角形的斜边长-include cosine function for calculating Y/X arc tangent, rounded upward, a few double precision decomposition of the final index, calculated length of the hypotenuse of the right triangle, etc.
- 2022-04-11 14:00:19下载
- 积分:1
-
a very attractive clock procedures
一个非常精美时钟程序-a very attractive clock procedures
- 2022-07-05 01:37:34下载
- 积分:1
-
2008年10月4日23:17:52
2008年10月4日23:17:52-October 4, 2008 23:17:52
- 2022-07-15 12:58:11下载
- 积分:1