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通用工业视频图像叠加的设计与实现，用于视频控制系统
通用工业视频图像叠加的设计与实现，用于视频控制系统-General Industrial video image overlay of the design and implementation for video control system
- 2022-03-23 23:57:07下载
- 积分：1
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RGB to YUV conversion
RGB to YUV conversion
- 2022-03-18 09:46:05下载
- 积分：1
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QuickBird satellite image geometric correction method of study is a paper, which...
快鸟卫星影像几何校正方法研究，是一篇论文，里面讲得方法很不错-QuickBird satellite image geometric correction method of study is a paper, which speaks very well
- 2023-07-31 00:40:03下载
- 积分：1
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c language morphological algorithms, suitable for beginners morphology emotional...
c语言编写的形态学算法，适合对形态学感性区的初学者和资深编程人员。-c language morphological algorithms, suitable for beginners morphology emotional areas and senior programmers.
- 2023-03-12 04:40:03下载
- 积分：1
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一个matlab阈值分割程序，再matlab下能运行
一个matlab阈值分割程序，再matlab下能运行-a Matlab threshold segmentation procedures, and then to run under Matlab
- 2022-02-21 05:25:19下载
- 积分：1
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I am a computer master' s thesis, Powell, and SA Hybrid Optimization of mutua...
本人的计算机硕士论文，Powell和SA混合优化的互信息图像配准，-I am a computer master" s thesis, Powell, and SA Hybrid Optimization of mutual information image registration,
- 2022-10-21 19:45:03下载
- 积分：1
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简单的图像
简单的图像处理程序-simple image-processing program
- 2022-08-25 00:10:55下载
- 积分：1
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简单的图像处理GUI平台，不过是全英文版的
简单的图像处理GUI平台，不过是全英文版的
-A simple image processing GUI platform, but the whole English
- 2023-03-02 00:00:03下载
- 积分：1
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Introduced the field of computer vision inherent in the world of laboratory rese...
介绍了世界范围内在计算机视觉领域的有突出研究成果的实验室极其个人，对介绍了计算机视觉领域的期刊杂志排名情况-Introduced the field of computer vision inherent in the world of laboratory research results highlight the very personal, and introduced the field of computer vision journals ranked
- 2022-07-11 13:55:07下载
- 积分：1
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geometry calculation of correlation algorithm can determine the function of the...
计算几何学的相关算法 可以根据这个函数确定两条线段在交点处的转向,比如确定p0 p1和p1 p2在p1处是左转还是右转，只要求(p2-p0)*(p1-p0)，若0则右转，=0则共线-geometry calculation of correlation algorithm can determine the function of the two segments to the intersection, such as identifying p0 p1 p1 and p2 p1 is the left or the right, only requirements (p2- p0)* (p1- p0), and if 0 right, a total = 0 line
- 2022-07-13 05:45:28下载
- 积分：1
