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using gall function for measure the algorithm
using gall function for measure the algorithm
- 2022-02-02 05:22:06下载
- 积分:1
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仿VB的InputBox
仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox仿VB的InputBox
- 2022-05-13 03:43:50下载
- 积分:1
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经典的矩形矩阵的各种问题产生的比赛时,是一个河..
经典矩形问题 生成各种矩阵是竞赛时经常考的一种题目,如何用C语言或C++生成以下形式几种矩阵:-classic rectangular matrix of various problems generated when the contest is a regular test subject, how to use C or C generated several matrix form :
- 2022-01-25 19:14:18下载
- 积分:1
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matlab SA algorithm
应用背景
智能优化,线性规划,路径寻优,。。。。。。。。。。。。。。。
关键技术matlab实现,求解优化问题,最优值寻找。。。
- 2022-02-24 18:16:56下载
- 积分:1
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曲线拟合小工具,包括对数拟合,多项式拟合,直线拟合,指数拟合,乘幂拟合...
曲线拟合小工具,包括对数拟合,多项式拟合,直线拟合,指数拟合,乘幂拟合-Curve fitting of small tools, including on the number of fitting, polynomial fitting, straight fitting, exponential fitting, by fitting power
- 2022-02-04 09:17:49下载
- 积分:1
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FSA的人工鱼
FSA人工鱼群算法用MATLAB编程实现。有很高的价值。体现了人工鱼群算法的特点。保证能运行。-FSA artificial fish-swarm algorithm with MATLAB Programming. Has a high value. Embodies the characteristics of artificial fish-swarm algorithm. Guarantee that it will run.
- 2022-02-02 09:34:46下载
- 积分:1
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对称对称计算的矩阵特征值与特征向量…
矩阵特征值和特征向量的计算关于对称矩阵的对称对角矩阵的何氏黑米荣变换它的对称三对角矩阵的所有特征值,特征向量的计算
- 2022-08-15 11:09:50下载
- 积分:1
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20M带宽高斯信道
程序说明:
1. 实现用2前导序列进行时间同步,但必须在高信噪比下,参考信噪比为30dB;进一步的优化见后续版本;
2. 实现一发多收情况下,通过AWGN信道的后的相位补偿合并,并进一步分析合并增益!
3. 请点击左侧文件开始预览 !预览只提供20%的代码片段,完整代码需下载后查看 加载中 侵权举报 打分 发表评论 暂无评论
- 2022-01-25 16:56:16下载
- 积分:1
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这个是SIMPSON求基公式的运用,求解任意一个函数在某个积分区间的结果。...
这个是SIMPSON求基公式的运用,求解任意一个函数在某个积分区间的结果。-SIMPSON this is the base formula for the use of a function to solve arbitrary points in a range of results.
- 2022-02-05 22:03:14下载
- 积分:1
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a description of the problem is : No. 1, 2, ..., n n clockwise direction by indi...
约瑟夫问题的一种描述是:编号为1,2,…,n的n个人按顺时针方向围坐一圈,没人持有一个密码。一开始人选一个正整数作为报数上限值m,从第一个人开始按顺时针自1开始报数,报到m是停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向上的下一个人开始重新从1报数,如此下去,直至所有人全部出列为止。-a description of the problem is : No. 1, 2, ..., n n clockwise direction by individuals sitting around a circle, no one holding a password. One person started as a positive integer limits on the number of reported m, from the first individuals to embark on the clockwise from a few reportedly started, the report m is reportedly stopped a few. M reported out of the list of his password as a new value m, from a clockwise direction in the next re-started from a newspaper a few, like that, until the total of all listed so far.
- 2022-02-03 16:31:48下载
- 积分:1