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Flex and JAVA configuration, the standard demand for documents, set up Eclipse p...
flex与java的配置，标准需求文档，设置eclipse提示功能。-Flex and JAVA configuration, the standard demand for documents, set up Eclipse prompts.
- 2022-03-13 14:42:19下载
- 积分：1
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此代码是用C++编写的，通过建立工程的方法来求一个数的阶乘。适合初学c++者！...
此代码是用C++编写的，通过建立工程的方法来求一个数的阶乘。适合初学c++者！-This code is used C++ Prepared, through the establishment of engineering methods to seek a number of factorial. Suitable for beginners c++ De!
- 2022-05-17 17:43:15下载
- 积分：1
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多项式的加减乘除运算，刚学C++写的，不是很好！
多项式的加减乘除运算，刚学C++写的，不是很好！-Polynomial addition and subtraction, multiplication and division calculations, just places C++ Write is not good!
- 2022-08-20 00:07:32下载
- 积分：1
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and passed a somewhat different, the overall situation is the hook, you see!
和刚才传的有些不同,这个是用的全局钩子,你们看一看吧!-and passed a somewhat different, the overall situation is the hook, you see!
- 2022-03-19 15:52:45下载
- 积分：1
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2 can be correlated quicksort example, relatively simple and obvious, easy to un...
两个可以对比的快速排序例子，比较浅显，容易理解，入门用-2 can be correlated quicksort example, relatively simple and obvious, easy to understand, started to use
- 2022-06-13 20:21:28下载
- 积分：1
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这是一个可以实现距离3 ~ 6km的通信程序，实现…
这个是一个可以实现3~6KM距离通讯的程序，实现过程都已经详细注释 硬件采用ADC得到原始数据 然后根据线路得编码情况得到数据
而且针对多节点 带了一个自适应的算法 这样就可以在总线上任意两个终端通讯-Can realize this is a distance of 3 ~ 6KM communications procedures, the realization of the process have been detailed notes ADC hardware used to be the raw data was then coded according to the situation of lines of data and for multi-node with an adaptive algorithm can then be in the bus on any two terminal communications
- 2022-01-26 06:19:35下载
- 积分：1
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一个简单的计算器程序，进行简单的数学计算，正确无误
一个简单的计算器程序，进行简单的数学计算，正确无误-A simple calculator program to carry out simple mathematical calculations are correct
- 2022-04-11 04:22:47下载
- 积分：1
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可以用于密码输入。需要的可以从中参看。挺不错的！
可以用于密码输入。需要的可以从中参看。挺不错的！-Can be used for password input. Need to be able to see. Very good!
- 2022-04-19 01:23:55下载
- 积分：1
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使用VC6.0开发的LoanArranger系统，包括整个工程文件
使用VC6.0开发的LoanArranger系统，包括整个工程文件-VC6.0 developed using LoanArranger system, including the entire project file
- 2022-03-10 15:50:54下载
- 积分：1
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there is a defect in only know that the secret and public key
还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected
- 2022-03-22 01:18:28下载
- 积分：1
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