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* 本算法用最小二乘法依据指定的M个基函数及N个已知数据进行曲线拟和
* 输入: m...
* 本算法用最小二乘法依据指定的M个基函数及N个已知数据进行曲线拟和
* 输入: m--已知数据点的个数M
* f--M维基函数向量
* n--已知数据点的个数N-1
* x--已知数据点第一坐标的N维列向量
* y--已知数据点第二坐标的N维列向量
* a--无用
* 输出: 函数返回值为曲线拟和的均方误差
* a为用基函数进行曲线拟和的系数,
* 即a[0]f[0]+a[1]f[1]+...+a[M]f[M].
-* The algorithm using the least-squares method based on the designated function of M and N-known curve data to be imported and* : m-- the known number of data points M* f-- From M* n vector function-- known data points the number N-1* x-- known data points of the first N-dimensional coordinates listed Vector* y-- known data points of the second N-dimensional coordinates shown in a vector*-- useless* Output : function return value to the curve-fitting and the mean square error* for the use of a base function and the curve fitting coefficients,* is a f [0] [0] a [1] f [a] ... a [M] f [M].
- 2022-03-31 18:42:38下载
- 积分:1
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Visual C++编程技巧之
1.如何获取应用程序的实例句柄?
2.如何通过代码获得应用程序主窗口的指针?
3.如何在程序中获得其他程序的 图标?...
Visual C++编程技巧之
1.如何获取应用程序的实例句柄?
2.如何通过代码获得应用程序主窗口的指针?
3.如何在程序中获得其他程序的 图标?
4.如何编程结束应用程序?如何编程控制windows的重新引导?
5.怎样加栽其他的应用程序?
6.确定应用程序的 路径
7.获得各种目录信息
8.如何自定义消息
-Visual C programming skills one. Application procedures for obtaining handle two examples. How the code was in the main application window to the three pointer. how the proceedings were other procedures icon 4. How to end application programming how to control windows programming guide the re-5. how to increase the planting of other applications 6. Application procedures for determining the Route 7. access to directory information 8. how to customize the news
- 2022-04-21 04:54:11下载
- 积分:1
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我们学校的上机作业 100个题目 题题经典
我们学校的上机作业 100个题目 题题经典-our schools operating on the 100 aircraft that subject that classic
- 2022-05-14 16:17:06下载
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六16
Six 16-Bit A/D Converters
Programmable Input Sample Rate
Simultaneous Sampling
- 2022-03-15 17:21:27下载
- 积分:1
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PID比例控制,用对水箱的液位的控制,通过调节阀的流量改变,来控制液位稳定...
PID比例控制,用对水箱的液位的控制,通过调节阀的流量改变,来控制液位稳定-pid
- 2023-08-05 12:50:03下载
- 积分:1
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简单的格式说明,主要用于linux下开发,是乱写的,建议大家不要看哦...
简单的格式说明,主要用于linux下开发,是乱写的,建议大家不要看哦-Simple format, mainly for linux under development, is the write without basis, it is recommended not to everyone看哦
- 2022-03-05 23:17:49下载
- 积分:1
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Can Bus Controller sja1000 source, great reference value
Can总线控制器sja1000的源程序,很有参考价值-Can Bus Controller sja1000 source, great reference value
- 2023-06-21 07:00:03下载
- 积分:1
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在瀑布的控制设计
Design of a Control in cascada
- 2023-08-02 07:25:03下载
- 积分:1
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三维图形的旋转 三维图形的旋转
三维图形的旋转 三维图形的旋转-rotating 3D graphics 3D graphics rotating 3D graphics rotation
- 2022-01-22 08:22:14下载
- 积分:1
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给你一个简短的想法,ZigBee。
Gives you a brief idea of zigbee.
- 2023-03-12 09:35:04下载
- 积分:1