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* 本算法用最小二乘法依据指定的M个基函数及N个已知数据进行曲线拟和
* 输入: m...
* 本算法用最小二乘法依据指定的M个基函数及N个已知数据进行曲线拟和
* 输入: m--已知数据点的个数M
* f--M维基函数向量
* n--已知数据点的个数N-1
* x--已知数据点第一坐标的N维列向量
* y--已知数据点第二坐标的N维列向量
* a--无用
* 输出: 函数返回值为曲线拟和的均方误差
* a为用基函数进行曲线拟和的系数,
* 即a[0]f[0]+a[1]f[1]+...+a[M]f[M].
-* The algorithm using the least-squares method based on the designated function of M and N-known curve data to be imported and* : m-- the known number of data points M* f-- From M* n vector function-- known data points the number N-1* x-- known data points of the first N-dimensional coordinates listed Vector* y-- known data points of the second N-dimensional coordinates shown in a vector*-- useless* Output : function return value to the curve-fitting and the mean square error* for the use of a base function and the curve fitting coefficients,* is a f [0] [0] a [1] f [a] ... a [M] f [M].
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Bus PC104PLUS technical documentation in English. PC104 bus information to devel...
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There are numbers 1,2,3,4, how many can be composed of mutually exclusive and no...
有1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少?
1.程序分析:可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去
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用vb编写遗传算法,实际应用部分(如适应度函数需要自己编写,程序中已注明),此为转载代码...
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DAB Channel Decoder Implementation Using FPGA
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