-
Soltek without extracting the software code, the installation can be extracted u...
soltek 本软件无解压码,解压安装即可用 简单使用 欢迎大家交流-Soltek without extracting the software code, the installation can be extracted using a simple Thank you, welcome you exchange
- 2023-03-17 18:45:05下载
- 积分：1
-
VisualC++6.0数字图像编码（丁贵广，计文平，郭宝龙）
VisualC++6.0数字图像编码（丁贵广，计文平，郭宝龙）-VC 6.0 Digital Image Coding (Ding-up Wen-ping, Guo Baolong)
- 2022-07-24 18:51:45下载
- 积分：1
-
This course is designed for individuals interested in developing their skills in...
This course is designed for individuals interested in developing their skills in Microsoft Visual C++ 6.0 while developing desktop applications. Topics include using the Microsoft Solutions Framework (MSF) building applications with the Microsoft Foundation Classes (MFC) creating user interfaces implementing application behaviors and working with persistent data. Also included are adding database support to applications creating Component Object Model (COM) components and ActiveX controls using MFC and the Active Template Library (ATL) Internet programming error handling, debugging, and testing and application deployment.
- 2022-04-01 21:44:40下载
- 积分：1
-
数组的一个小例子 具体说明数组中的一些用法和属性
数组的一个小例子 具体说明数组中的一些用法和属性-A small example of the array to specify an array of some of the usage and attributes
- 2023-04-01 01:40:04下载
- 积分：1
-
自己实现的推箱子游戏，用vc6.0编译成功，有一定的价值
自己实现的推箱子游戏，用vc6.0编译成功，有一定的价值-Realize their own game of Sokoban with vc6.0 compile successful, has some value
- 2022-09-23 00:35:03下载
- 积分：1
-
初轨确定
测站在地心赤道坐标系下的位置。计算平格林尼治时角接下来求目标在地心赤道坐标系下的方向余弦下面利用高斯法求解r2、v2下面开始改进精度；最后利用求出的r2、v2计算轨道根数
- 2022-02-07 21:36:12下载
- 积分：1
-
从cclockctrl
来自PJ Naughter的CClockCtrl-from the CClockCtrl
- 2022-05-19 17:54:15下载
- 积分：1
-
物体的工艺
The Craft of Object-Oriented Programming
- 2022-09-06 04:20:03下载
- 积分：1
-
Driver and Sources for Marvell SD8686 Chip under Linux v9.70.3.p24
Driver and Sources for Marvell SD8686 Chip under Linux v9.70.3.p24-Driver and Sources for Marvell SD8686 Chip under Windows XP embedded
- 2022-03-21 13:06:22下载
- 积分：1
-
约瑟夫环（Joseph）问题的一种描述是：编号为1，2，…，n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始人选一个正整数作为报数上限值m，从...
约瑟夫环（Joseph）问题的一种描述是：编号为1，2，…，n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始人选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从它在顺时针方向的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序-Joseph Central (Joseph) a description of the problem is: numbered 1,2, ..., n of n individuals according to a clockwise direction around a circle, each holding a password (positive integer). The beginning of a positive integer as a candidate at a number of upper limit of m, from the first individual to embark on the clockwise direction since the beginning of the order of 1 is reported the number of stops required to report back at a few m. Those who reported m out of his password as the new value of m, in a clockwise direction from the next person to start off again from the 1, and so on, until all that out until all. Try to design a procedure to derive the column order
- 2022-02-10 01:58:28下载
- 积分：1
