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Test02
读取DXF文件(2000,2002版本),包括了分层管理数据的思想,供大家参考(read DXF files (version 2000, 2002), including a hierarchical data management thinking, for your reference)
- 2007-06-08 11:16:22下载
- 积分：1
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eg1_IndependentProject_GPIO
说明： 28035的GPIO配置例程，实现流水灯相关的功能(28035 GPIO configuration routines for implementing water-light related functions)
- 2020-11-19 11:39:37下载
- 积分：1
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串口显示步进电机（12864）
12864串行显示 步进电机 STC89C52控制 按键控制正转 反转 转动次数
- 2022-02-11 20:04:10下载
- 积分：1
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VC-Matlab-hunhebiancheng
对利用vc和matlab的混合编程技术进行介绍(For mixed use vc and matlab programming techniques are introduced)
- 2011-09-17 12:00:10下载
- 积分：1
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PostProgress
数控五轴速度后置处理源程序，实现速度后置处理(post progress)
- 2021-03-16 13:19:21下载
- 积分：1
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mostvalurs
/*题目内容：有n件产品，编号分别为0,1,2,3,4,5,6....n-1，它们的重量分别是a[0],a[1],a[2]......a[n-1],它们的价值分别是b[0],b[1].....b[n-1],现在给你个承重为w的背包，如何让背包里装入的物品具有最大的价值总和？
*/ (this is a program that may help you do something )
- 2014-07-24 11:39:22下载
- 积分：1
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jose
约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。
(Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)
- 2015-01-09 17:28:41下载
- 积分：1
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1
说明： matlab程序 半参数模型两阶段估计的参考程序(Two stage estimation of MATLAB program semi parametric model)
- 2018-06-04 02:06:17下载
- 积分：1
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MTI-1
STM32F777驱动MTI-1传感器,测试通过，并挂机稳定性OK(STM32F777 FOR MTI-1 OF XSENS)
- 2020-11-27 15:39:30下载
- 积分：1
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PriceAction策略源码
说明： 该EA程序可用于外汇市场价格行为分析，趋势强度计算，可自动交易(The EA can be used for foreign exchange market data analysis, trend strength calculation, can be automatically traded)
- 2020-06-19 16:20:02下载
- 积分：1
